Ask question

Ask question

All categories

olya-2409 [2.1K]

3 years ago

14

y varies directly with x, and y = 9 when x = 2. What is the value of y when x = 3? Enter your answer in the box.

1 answer:

Reptile [31]3 years ago

7 0

Let y=kx
9=2k
k=4.5
when x=3
y=kx becomes
y=4.5 x 3
=13.5

You might be interested in

If George received $ 78.00 for his work at Weaver's Store, and he was paid $ 6.00 per hour, how many hours did he work?

mihalych1998 [28]

13 hours
78.00 ÷ 6.00 equals 13 hours
6×13 equals 78

3 0

4 years ago

Read 2 more answers

Select the three expressions that are equivalent to 8h + 4g. * 3 points

WINSTONCH [101]

<span>4(2h + g)
</span><span>4h + 4h +3g + g
</span>2(4h + 2g)

4 0

3 years ago

Read 2 more answers

Make q the subject of the formula 2(q+p) = 1 + 5 q

CaHeK987 [17]

Answer:

q = 2/3p - 3

Step by step:

2q+2p = 1+5q
2q - 5q = -2p + 1
-3q = -2p + 1
q = 2/3p - 3

3 0

3 years ago

Find dy/dx any one <br>x=acost , y=asint

dangina [55]

Answer:

$x=a \cos t \implies \dfrac{dx}{dt}=-a \sin t$

$y= a \sin t \implies \dfrac{dy}{dt}=a \cos t$

Using the chain rule:

$\begin{aligned}\implies \dfrac{dy}{dx} & =\dfrac{dy}{dt} \times \dfrac{dt}{dx}\\\\& = a \cos t \times \dfrac{1}{-a \sin t}\\\\& = \dfrac{a \cos t}{-a \sin t}\\\\& = - \dfrac{\cos t}{\sin t}\\\\& = - \cot t\end{aligned}$

8 0

2 years ago

A toy rocket is launched from a platform 33 feet above the ground at a speed of 83 feet per second. The height of the rocket in

yanalaym [24]

Answer:

c. 138 feet

Step-by-step explanation:

h(t) = −16t^2 + 83t + 33

At3 seconds

h(3) = -16(3^2) + 83(3) + 33

h(3) = -16(9) + 249 + 33

h(3) = -144 + 249 + 33

h(3) = 138

c. 138 feet

3 0

2 years ago