Answer:
Step-by-step explanation:
2^0 is less than or equal to 1!, because 1<= 1
if 2^n <= (n+1)!, we wish to show that 2^(n+1) <= (n+2)!, since
(n+2)! = (n+1)! * (n+2), and (n+1)!>= 2^n, then we want to prove that n+2<=2, which is always true for n>=0
About 49 pounds
$5.75 x 2 = 11.50
561.60 / 11.50 = 48.83 (round)
49 lbs
We know that
the euclid's division A/B implies A= BQ + R
wher Q = the quotient, and R is the remainder
<span>after doing euclid's division, (3x^3+15x^2+17x+3)/x+5 = 3x²+17and R= - 82
so </span>(3x^3+15x^2+17x+3= (3x²+17) (x+5) -82
the answer is x^3+15x^2+17x+3= (3x²+17) (x+5) - 82
Answer: Please see explanation column for answer
Step-by-step explanation:
According to sequence 2, 6, 18, 54, 162
--we can see that it is a geometric sequence since to go from one term to the next requires us to multiply by 3 which is called the common ratio which is gotten by dividing the next by the previous.
ie term 2/ term 1= 6/2 = 3
term 3/ term 2= 18/6= 3
term 4/ term 3= 54/28= 3
term 5 / term 4= 162/54=3
term 6 will therefore be 162 x3 = 486
and term 7 = 486 x 3=1,458 and so on
Recall that nth term of GP is
Tn = ar^n-1
Where a= first term
r= common ratio
n= term
such that to easily find particular term, we plug in the values and calculate
for example the 10th term of the above sequence
Tn = ar^n-1
= 2 X 3 ^(10-1)
2 X 3^9
T10 =39,366
