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Doss [256]
3 years ago
14

110$ for 16ft find the unit rate ​

Mathematics
1 answer:
Neporo4naja [7]3 years ago
8 0

Answer:

6.875 dollars per feet

Step-by-step explanation:

110/16

6.875

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Prove usin's Mathematical induction 2^n ≤(n+1)!, for n≥0​
Westkost [7]

Answer:

Step-by-step explanation:

2^0 is less than or equal to 1!, because 1<= 1

if 2^n <= (n+1)!, we wish to show that 2^(n+1) <= (n+2)!, since

(n+2)! = (n+1)! * (n+2), and (n+1)!>= 2^n, then we want to prove that n+2<=2, which is always true for n>=0

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1 year ago
Mai's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs Mai $4.10 per pound, and type B co
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About 49 pounds

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49 lbs
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2 years ago
Factor 7(x − 3)2 − 4(x − 3) − 3 completely.
Nezavi [6.7K]
7(x-3)^2-4(x-3)-3\\\\substitute\ t=x-3,\ then\ we\ have\\\\7t^2-4t-3\\\\a=7;\ b=-4;\ c=-3\\\\\Delta=b^2-4ac\\\\\Delta=(-4)^2-4\cdot7\cdot(-3)=16+84=100\\\\t_1=\dfrac{-b-\sqrt\Delta}{2a};\ t_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{100}=10\\\\t_1=\dfrac{-(-4)-10}{2\cdot7}=\dfrac{4-10}{14}=\dfrac{-6}{14}=-\dfrac{3}{7}\\\\t_2=\dfrac{-(-4)+10}{2\cdot7}=\dfrac{4+10}{14}=\dfrac{14}{14}=1\\\\7t^2-4t-3=7\left(t+\dfrac{3}{7}\right)(t-1)=(7t+3)(t-1)\\\\=(7(x-3)+3)(x-3-1)=(7x-21+3)(x-4)\\\\=\boxed{(7x-18)(x-4)}
7 0
3 years ago
Which of the following expressions is this one equivalent to?
Alborosie
We know that 
the euclid's division A/B implies A= BQ + R
wher Q = the quotient, and R is the remainder
<span>after doing euclid's division, (3x^3+15x^2+17x+3)/x+5 = 3x²+17and R= - 82
so </span>(3x^3+15x^2+17x+3= (3x²+17) (x+5) -82

the answer is x^3+15x^2+17x+3= (3x²+17) (x+5) - 82
8 0
3 years ago
Read 2 more answers
Question Progress
Anastaziya [24]

Answer: Please see explanation column for answer

Step-by-step explanation:

According to sequence   2, 6, 18, 54, 162

--we can see that it is a geometric sequence since to go from one term to the next requires us to  multiply by 3 which is called the common ratio which is gotten by dividing the next by the previous.

ie term 2/ term 1= 6/2 = 3

term 3/ term 2= 18/6= 3

term 4/ term 3= 54/28= 3

term 5 / term 4= 162/54=3

term 6 will therefore be 162 x3 = 486

and term 7 = 486 x 3=1,458 and so on

Recall that  nth term of GP is

Tn = ar^n-1

Where a= first term

r= common ratio

n= term

such that to easily find particular term, we  plug in the values and calculate

for example the 10th term of the above sequence

Tn = ar^n-1

= 2 X 3 ^(10-1)

2 X 3^9

T10 =39,366

4 0
3 years ago
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