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3 years ago

15

What is the average rate of change of f(x), represented by the graph, over the interval [-2, 2]?

2 answers:

irina [24]3 years ago

7 0

On plato the answer is D=0

Molodets [167]3 years ago

5 0

To get the average rate of change (ARC) of f(x) over [x1, x2], we use the formula:
ARC = ( f(x2) - f(x2) ) / (x2 - x1)

From the graph
f(2) = 4
f(-2) = 4

Plugging in the values into the formula:
ARC = (4 - 4) / (2 - (-2) )
ARC = 0

The points connecting (-2,4) amd (2,4) is a horizontal line that is the rate of change is 0.

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i have 17 coins. N of them are nickels and the rest are dimes. write an expression in two different ways for the amount of money

valkas [14]

Answer:

Step-by-step explanation:

(N)0.05 + (17-N)0.1 = M; M = amount of money I have.

Or 1.7-0.05N = M.

7 0

3 years ago

The height of the tunnel at the center is 35ft, and the vertical clearance must be 21 ft at a point of 8ft from the center. Find

Zinaida [17]

Answer:

y=-0.215x^2+35

Step by Step:

Let, $h=0$ , $k=35$ , $x=8$ , $y=21$

We know that, the general equation of the parabola.

$y-k = a(x-h)^2$

$\Rightarrow y=a(x-h)^2+k .........(i)$

Substitute the value of $h, k, x, y$ in equation $(i)$ and find the value of $a.$

$21=a(8-0)^2+35$

$\Rightarrow 21=a\times 8^2+35$

$\Rightarrow 21=64a+35$

$\Rightarrow 64a=21-35$

$\Rightarrow 64a=-14$

$\Rightarrow a=\frac{-14}{65}$

$\Rightarrow a=-0.215$

Hence, the equation of the parabola is:

$y=-0.215x^2+35$

8 0

3 years ago

Which binomial is a factor of 12x^2 - x - 20

stellarik [79]

Answer:

12x² - x - 20 = (4x+5)(3x−4)

3 0

2 years ago

Need help with question 2

yuradex [85]

1,5,8 would be the correct answer

8 0

3 years ago

Read 2 more answers

A meteorologist is studying the speed at which thunderstorms travel. A sample of 10 storms are observed. The mean of the sample

dezoksy [38]

Answer:

The 95% confidence interval for the true mean speed of thunderstorms is [10.712, 13.688].

Step-by-step explanation:

Given information:

Sample size = 10

Sample mean = 12.2 mph

Standard deviation = 2.4

Confidence interval = 95%

At confidence interval 95% then z-score is 1.96.

The 95% confidence interval for the true mean speed of thunderstorms is

$CI=\overline{x}\pm z*\frac{s}{\sqrt{n}}$

Where, $\overline{x}$ is sample mean, z* is z score at 95% confidence interval, s is standard deviation of sample and n is sample size.

$CI=12.2\pm 1.96\frac{2.4}{\sqrt{10}}$

$CI=12.2\pm 1.487535$

$CI=12.2\pm 1.488$

$CI=[12.2-1.488, 12.2+1.488]$

$CI=[10.712, 13.688]$

Therefore the 95% confidence interval for the true mean speed of thunderstorms is [10.712, 13.688].

4 0

3 years ago