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liq [111]
2 years ago
14

How do I do regular fractions and equivalent fractions

Mathematics
2 answers:
jenyasd209 [6]2 years ago
8 0
Regular= 3/5  equivalent= 6/10  just multiply the top and bottom by the same number.

Travka [436]2 years ago
5 0
Just multiple the two numbers by any two same numbers to get an equivalent fraction. For example 1/2 multiple 1 by 2 and 2 by 2 which gives you the equivalent fraction 2/4
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Evaluate the expression (- n) ^ (n + n) + n ^ (n - n) , when n = 2
sladkih [1.3K]

Answer:

17

Step-by-step explanation:

Substitute the value of the variable and simplify.

(-(2))^{(2+2)} +2^{(2-2)}

-2x^{2+2} =2^{4} = 16

2^{2-2} =2^{0}

Anything raised to the power of 0 is one.

16 + 1 = 17

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3 years ago
Whats ski mask first ever song<br>​
Lelu [443]

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Step-by-step explanation:

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2 years ago
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A 1000-liter (L) tank contains 500 L of water with a salt concentration of 10 g/L. Water with a salt concentration of 50 g/L flo
djverab [1.8K]

Answer:

a) y(t)=50000-49990e^{\frac{-2t}{25}}

b) 31690.7 g/L

Step-by-step explanation:

By definition, we have that the change rate of salt in the tank is \frac{dy}{dt}=R_{i}-R_{o}, where R_{i} is the rate of salt entering and R_{o} is the rate of salt going outside.

Then we have, R_{i}=80\frac{L}{min}*50\frac{g}{L}=4000\frac{g}{min}, and

R_{o}=40\frac{L}{min}*\frac{y}{500} \frac{g}{L}=\frac{2y}{25}\frac{g}{min}

So we obtain.  \frac{dy}{dt}=4000-\frac{2y}{25}, then

\frac{dy}{dt}+\frac{2y}{25}=4000, and using the integrating factor e^{\int {\frac{2}{25}} \, dt=e^{\frac{2t}{25}, therefore  (\frac{dy }{dt}+\frac{2y}{25}}=4000)e^{\frac{2t}{25}, we get   \frac{d}{dt}(y*e^{\frac{2t}{25}})= 4000 e^{\frac{2t}{25}, after integrating both sides y*e^{\frac{2t}{25}}= 50000 e^{\frac{2t}{25}}+C, therefore y(t)= 50000 +Ce^{\frac{-2t}{25}}, to find C we know that the tank initially contains a salt concentration of 10 g/L, that means the initial conditions y(0)=10, so 10= 50000+Ce^{\frac{-0*2}{25}}

10=50000+C\\C=10-50000=-49990

Finally we can write an expression for the amount of salt in the tank at any time t, it is y(t)=50000-49990e^{\frac{-2t}{25}}

b) The tank will overflow due Rin>Rout, at a rate of 80 L/min-40L/min=40L/min, due we have 500 L to overflow \frac{500L}{40L/min} =\frac{25}{2} min=t, so we can evualuate the expression of a) y(25/2)=50000-49990e^{\frac{-2}{25}\frac{25}{2}}=50000-49990e^{-1}=31690.7, is the salt concentration when the tank overflows

4 0
3 years ago
Solve for x. PLEASE HELP ASAP WILL GIVE BRAINLIEST ANSWER
murzikaleks [220]

Answer:

x = 2.6  

Step-by-step explanation:

To find x, you need to find how many times you need to multiply 25 to get 65. Using reverse operations will make this easier. 65 / 25 = 2.6. We can check this by multiplying 25 by 2.6, and we get 65.

3 0
3 years ago
A cake company makes cheesecakes with a circumference of approximately 75.36 cm. They need to design their boxes to offer single
Umnica [9.8K]

Answer:

12

Step-by-step explanation:

I'm not entirely sure abt this but here goes nothing

75.36 divided by 3.14 = 24

24 = diameter

radius = 12

7 0
2 years ago
Read 2 more answers
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