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lana [24]
3 years ago
14

3.) You are wrapping a present in shape of a tube,

Mathematics
1 answer:
sertanlavr [38]3 years ago
5 0

Answer:

56π = 175.929, so no.

Step-by-step explanation:

Surface area formula: 2B+Ph (where B is area of the base, P is perimeter of the base, and h is height.)

2(4π) + 4π(12)

8π +48π

56π = 175.9 ft^2

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Decomposition, find f(x) and g(x) so that the function can be
andrew11 [14]

Answer:

steps below

Step-by-step explanation:

f(x) = x + 5

g(x) = x - 4

f(g(x)) = f(x-4) = (x-4) + 5

3 0
3 years ago
What is the height of the tree in the image below? 10 points Wall 4 6 ft 24 O I foot O 36 foot None of the above
Zinaida [17]

16 ft

Explanation

Step 1

because the ligth comes in the same angle, we have 2 similar triangles .

so,as the triangles are similar,the ratio of the shorter leg to the bigger leg must be equal.

\begin{gathered} ratio=\frac{shorter\text{ leg}}{\text{bigger leg}} \\ ratio1=ratio2 \\ \frac{h}{24}=\frac{4}{6} \end{gathered}

Step 2

solve for h

\begin{gathered} \frac{h}{24}=\frac{4}{6} \\ \text{cross multiply} \\ 6\cdot h=4\cdot24 \\ 6h=96 \\ \text{divide boths} \\ \frac{6h}{6}=\frac{96}{6} \\ h=16 \end{gathered}

therefore, the heigth of the tree is 16 ft

5 0
10 months ago
Add the following rational number7/-27 and 11/18
poizon [28]

Answer:

19/54

Step-by-step explanation:

- 7/27 + 11/18

LCM of the 27, 18 is 54

- 7/27 * (2/2) + 11/18 * (3/3)

- 14/54 + 33/54

33 - 14/54

19/54

please mark me brainlist

3 0
2 years ago
explain why the amount of propane in a grill’s tank and the time spent grilling could represent an inverse variation
Oxana [17]

The obvious answer is because propane is a gas at room temperature, while 2-propanol is a liquid at room temperature.

That happens because the intermolecular forces that exist between 2-propanol, or isopropyl alcohol, molecules are stronger than those that exist between propane molecules.

3 0
3 years ago
Solve for x and y.<br><br> 4x-3y=16<br> -2x+4y=-2<br><br> DUE 2/7/17!
Trava [24]
\left \{ {{4x-3y=16\:(I)} \atop {-2x+4y=-2\:(II)}} \right.

<span>Multiply the 2nd equation by (-4). This will eliminate the x's when you add the two new equations together.
</span>\left \{ {{4x-3y=16\:\:\:\:\:\:\:\:\:\:} \atop {-2x+4y=-2\:*(-4)}} \right.
\left \{ {{\diagup\!\!\!\!4x-3y=16} \atop {-\diagup\!\!\!\!4x+8y=-4}} \right.
--------------------
5y = 12
\boxed{\boxed{y =  \frac{12}{5}}}\end{array}}\qquad\quad\checkmark

Let's replace the value found in the first equation:
4x-3y=16\:(I)
4x-3*( \frac{12}{5}) =16
4x -  \frac{36}{5} = 16
least common multiple (5)
\frac{20x}{\diagup\!\!\!\!5} - \frac{36}{\diagup\!\!\!\!5} = \frac{80}{\diagup\!\!\!\!5}
20x - 36 = 80
20x = 80 + 36
20x = 116
x = \frac{116}{20} \frac{\div4}{\div4} \to\: \boxed{\boxed{x = \frac{29}{5} }}\end{array}}\qquad\quad\checkmark



4 0
3 years ago
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