Using the t-distribution, it is found that:
a. The <u>margin of error</u> is of 4.7 homes.
b. The 98% confidence interval for the population mean is (19.3, 28.7).
The information given in the text is:
- Sample mean of
. - Sample standard deviation of
. - Sample size of
.
We are given the <u>standard deviation for the sample</u>, which is why the t-distribution is used to solve this question.
The confidence interval is:

The margin of error is:

Item a:
The critical value, using a t-distribution calculator, for a two-tailed <u>98% confidence interval</u>, with 23 - 1 = <u>22 df</u>, is t = 2.508.
Then, the <em>margin of error</em> is:

Item b:
The interval is:


The 98% confidence interval for the population mean is (19.3, 28.7).
A similar problem is given at brainly.com/question/15180581
i believe it's 22.5 out of 45 to get exactly .500
Answer:
A I think im fairly certain
Step-by-step explanation: