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3 years ago

Below is a proof showing that the sum of a rational number and an irrational number is an irrational number.

Mathematics

2 answers:

amid [387]3 years ago

6 0

Answer:

Step-by-step explanation:

x+(-a) is rational because it is the sum of two rational numbers. You can see them as fractions, if x and -a are rational numbers they can be represented by fractions and the sum of two fractions is a fraction, that is a rational number.

sp2606 [1]3 years ago

4 0

<span>B. it is the sum of two irrational numbers.</span>

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s2008m [1.1K]

If $\frac{3+\sqrt{8} }{3-\sqrt{8} } +\frac{3-\sqrt{8} }{3+\sqrt{8} }=a+b\sqrt{2}$ , the value of a and b is given as a = 34 and b = 0

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An equation is an expression that shows the relationship between two or more variables or numbers.

$\frac{3+\sqrt{8} }{3-\sqrt{8} } +\frac{3-\sqrt{8} }{3+\sqrt{8} }\\ \\\frac{9+6\sqrt{8}+8+9-6\sqrt{8}+8 }{(3-\sqrt{8} )(3+\sqrt{8} )} \\\\\frac{34}{9-8} =34+0\sqrt{2}$

If $\frac{3+\sqrt{8} }{3-\sqrt{8} } +\frac{3-\sqrt{8} }{3+\sqrt{8} }=a+b\sqrt{2}$ , the value of a and b is given as a = 34 and b = 0

Find out more on equation at: brainly.com/question/2972832

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2 years ago

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kipiarov [429]

It would belong to integers, rational, and real numbers.

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Step-by-step explanation:

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