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FromTheMoon [43]
3 years ago
13

Who is the person in the end of intergalctic?

Mathematics
1 answer:
andrew11 [14]3 years ago
6 0
Its lil turbo and mr beef cKE

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ericka, a realestate agent, specializes in leasing apartments. her commision is 150% of her clients monthly rent. last week, she
Viefleur [7K]

Probably Erica is charging 150% of the first month of rental/leasing an apartment.

$850 being 150% of the rental/ lease for a month

the amount Erica's fee is based is $850×100:150=$566.(6)

5 0
3 years ago
Please help! 25points! pleaseeee helppppp
BaLLatris [955]

Answer: this is difficult


Step-by-step explanation:


6 0
3 years ago
Please helpp, thank youuu.
Mariulka [41]

Answer:

16ft

Step-by-step explanation:

use pythagreom thereom

12^2+b^2=20^2 solve

144+b^2=400

b^2= 256 square it

b= 16

4 0
2 years ago
Read 2 more answers
[4]
Tanya [424]

Answer:

Angle ACD = 38°

Step-by-step explanation:

The full, correct question is presented the attached image to this solution.

Given

Point O is the centre if the circle

Points A, B, C and D are points on the circle

Angle AOB = 140°

Angle OAC = 14°

Angle AOB = 2 × (Angle ACB) [angle subtended at the centre of the circle is twice the angle subtended at the circumference of the circle)

140° = 2 × (Angle ACB)

Angle ACB = (140°/2) = 70°

(Angle AOB) + (Angle OAB) + (Angle ABO) = 180° [sun of angles in a triangle is 180°]

But Angle OAB = Angle ABO = a [base angles of an iscosceles triangle are equal since OA and OB are both radii for the circle O)

(Angle AOB) + (Angle OAB) + (Angle ABO) = 180°

140° + a + a = 180°

2a = 40°

a = (40/2) = 20°

Angle OAB = Angle ABO = 20°

Angle CAB = (Angle OAC) + (Angle OAB) = 14° + 20° = 34°

Triangle ADC is an iscosceles triangle, hence,

Angle DAC = Angle ACD = x [base angles of an iscosceles triangle are equal]

But

(Angle DCB) + (Angle DAB) = 180° [Opposite angles of a cyclic quadilateral (a quadilateral inscribed in a circle) sum up to give 180°]

Angle DCB = (Angle DCA) + (Angle ACB) = (x + 70°)

Angle DAB = (Angle DAC) + (Angle CAB) = (x + 34°)

(Angle DCB) + (Angle DAB) = 180°

(x + 70°) + (x + 34°) = 180°

2x + 104° = 180°

2x = 180° - 104° = 76°

x = (76°/2) = 38°

Angle DAC = Angle ACD = 38°

Angle ACD = 38°

Hope this Helps!!!

7 0
3 years ago
Help!?!?!?!??!!!!!!!!!!!!!!
Fynjy0 [20]

Answer:

Step-by-step explanation:

Answer d) looks good

8 0
2 years ago
Read 2 more answers
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