Question

How many ways can you divide 9 children into a team of 4, a team of 3, and a team of 2?

Answer 1

Answer:

1260 ways

Step-by-step explanation:

We want to arrange n people into x roles.

$m_{0}$ is the number of people for the first role.

$m_{1}$ is the number of people for the second role.

$m_{x}$ is the number of people for the xth role.

The total number of arrangents is:

$T = \frac{n!}{m_{0}!m_{1}!...m_{x}!}$

In this question:

9 people

Team of 4

Team of 3

Team of 2

How many ways:

$T = \frac{9!}{4!3!2!} = 1260$