Answer:
x + 2y - 5 = 0
Step-by-step explanation:
We can see that , the graph passes through (0,2.5) and (5,0) . Therefore the ,
- x intercept is 5
- y intercept is 2.5
We can use the intercept form of equation as ,
=> x/a + y/b = 1
=> x/5 + y/2.5 = 1
=> x + 2y/5 = 1
=> x + 2y = 5
=> x + 2y -5 = 0 .
This equation can be verified by plotting the graph .[ Refer to attachment ]
<h3><u>Hence </u><u>the</u><u> </u><u>equation</u><u> of</u><u> </u><u>the</u><u> line</u><u> is</u><u> </u><u>x </u><u>+</u><u> </u><u>2</u><u>y</u><u> </u><u>-</u><u> </u><u>5</u><u> </u><u>=</u><u> </u><u>0</u><u> </u><u>.</u></h3>
Answer:
add 4
Step-by-step explanation:
x^2-4x
Take the coefficient of the x term
-4
Divide it by 2
-4/2 =-2
Square it
(-2)^2 = 4
This is what we add to each side
x^2-4x +4 = 4
Hello,
Shall we begin?
= 2 + 2×9÷3+10-45+21
= 2 + 18 : 3 + 10 - 45 + 21
= 2 + 6 + 10 - 45 + 21
= - 6
Answers: - 6
Answer: The diagram shows a square ABCD with a point inside it which is 1 unit from D, 2 units from A and 3 units from B. Let angle APD= theta . (a) Show that theta = (3pi)/4 (b Show that if P is outside the square , then theta = pi/4 () Is the situation possible if P is 3 units from C instead of from B?
Step-by-step explanation: