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2 years ago

In succession 6, 18, 21, 63, 66, the number that follows is ...

Mathematics

2 answers:

katrin2010 [14]2 years ago

5 0

I believe its 198. that's what i got adleast

ki77a [65]2 years ago

3 0

198
It goes times add 3 and then this pattern repeats.

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Rewrite the equation of the parabola in vertex form. y= x2 + 8x - 21

sergey [27]

Answer:

$y=(x+4)^{2}-37$

Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

$y=a(x-h)^{2}+k$

where

(h,k) is the vertex of the parabola

if a> 0 then the parabola open upward (vertex is a minimum)

if a< 0 then the parabola open downward (vertex is a maximum)

In this problem we have

$y=x^{2}+8x-21$

Convert to vertex form

Complete the square

$y+21=x^{2}+8x$

$y+21+16=(x^{2}+8x+16)$

$y+37=(x^{2}+8x+16)$

$y+37=(x+4)^{2}$

$y=(x+4)^{2}-37$ --------> equation in vertex form

The vertex is the point $(-4,-37)$

the parabola open upward (vertex is a minimum)

4 0

2 years ago

Read 2 more answers

You create 15 centerpieces for a party in 5 hours.

barxatty [35]

A) 3 centerpieces per hour because 15/5 = 3
b) 14 hours, because 3 goes into 42 14 times exactly.
Hope this helps!

7 0

2 years ago

Write three fractions between 3/10 and 9/10

Norma-Jean [14]

Answer:

4/10, 5/10, 6/10 are all fractions in between 3/10 and 9/10

Step-by-step explanation:

8 0

3 years ago

HELP PLEASE 10 POINTS

UkoKoshka [18]

Answer:

Step-by-step explanation:

6 0

2 years ago

NO LINKS!! Use the method of substitution to solve the system. (If there's no solution, enter no solution). Part 11z

Roman55 [17]

Answer:

$(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}$

$(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}$

Step-by-step explanation:

Given system of equations:

$\begin{cases}y=x^2-9\\y=4x-4\end{cases}$

To solve by the method of substitution, substitute the first equation into the second equation and rearrange so that the equation equals zero:

$\begin{aligned}x^2-9&=4x-4\\x^2-4x-9&=-4\\x^2-4x-5&=0\end{aligned}$

Factor the quadratic:

$\begin{aligned}x^2-4x-5&=0\\x^2-5x+x-5&=0\\x(x-5)+1(x-5)&=0\\(x+1)(x-5)&=0\end{aligned}$

Apply the <u>zero-product property</u> and solve for x:

$\implies x+1=0 \implies x=-1$

$\implies x-5=0 \implies x=5$

Substitute the found values of x into the <u>second equation</u> and solve for y:

$\begin{aligned}x=-1 \implies y&=4(-1)-4\\y&=-4-4\\y&=-8\end{aligned}$

$\begin{aligned}x=5 \implies y&=4(5)-4\\y&=20-4\\y&=16\end{aligned}$

Therefore, the solutions are:

$(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}$

$(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}$

6 0

8 months ago

Read 2 more answers