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VARVARA [1.3K]
2 years ago
6

Find three ratios that are equivalent to 2 4. A. 8 16 B. 10 24 C. 4 8 D. 3 5 E. 6 12 F. 12 6

Mathematics
1 answer:
xenn [34]2 years ago
3 0

Answer:

A, C, and E good luck

Step-by-step explanation:

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What is the least common denominator for 2/5 + 3/7
muminat

Answer:

35

Step-by-step explanation:

2/5 + 3/7

the least common denominator is 35 because 14/35 + 15/35.

3 0
2 years ago
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Mazyrski [523]
There’s a 2/6 chance that the science project would be first
3 0
2 years ago
7 = -x+3. Consider the line y = Find the equation of the line that is parallel to this line and passes through the point (-5, 6)
artcher [175]

Answer with explanation:

The equation of line is, y= -x +3

→x+y-3=0---------(1)

⇒Equation of line Parallel to Line , ax +by +c=0 is given by, ax + by +K=0.

Equation of Line Parallel to Line 1 is

  x+y+k=0

The Line passes through , (-5,6).

→ -5+6+k=0

→ k+1=0

→k= -1

So, equation of Line Parallel to line 1 is

x+y-1=0

⇒Equation of line Perpendicular  to Line , ax +by +c=0 is given by, bx - a y +K=0.

Equation of Line Perpendicular to Line 1 is

  x-y+k=0

The Line passes through , (-5,6).

→ -5-6+k=0

→ k-11=0

→k= 11

So, equation of Line Parallel to line 1 is

x-y+11=0

4 0
2 years ago
Please help! How on earth do I do this? In the year 2015, Anna bought a new car for $36,000. In 2017, she was told that the valu
Klio2033 [76]

Part A

Purchase Value of Anna's Car in 2015 = $36,000

Depreciated Value of Anna's Car in 2017 = $25,000

We know that the value of the car is depreciating linearly.


From the above data, we can see that the value of the car has reduced by $36,000-$25,000 = $11,000 over 2 years.

⇒ Per year the value has been depreciated by \frac{11000}{2}

⇒ Per year the value has been depreciated by $5,500

So if the value of a car in 2015 is V₀ then value of the car after t years can be determined by the below function:

V (t) = V₀ - (t*5,500), where t indicates the years passed since 2015

OR V (t) = 36,000 - (t*5,500), where t indicates the years passed since 2015

Part B

Suggested value of Anna's car for trade in option in 2018 = $15,000

In 2018, 3 years would have been passed since 2015. Using the value of t = 3 in the function determined in Part A:

V(3) = V₀ - (3*5,500)

⇒ V(3) = 36,000 - (16,500)

⇒ V(3) = $19,000

From the above calculations, we can see that the value of the car in 2018 should be $19,000, however the suggested value for trade in is indicated as $15,000 which is lower than what the value of the car should be. Hence, basis linear depreciation, the $15,000 value is not fair for the car in 2018.

3 0
2 years ago
Simplify this expression : 2x(x-1)-3x^2-(5x-4)
Setler [38]

Answer:

-x^2 - 7x + 4

Step-by-step explanation:

2x(x - 1) - 3x^2 - (5x - 4)

= 2x^2 - 2x - 3x^2 - 5x + 4

Adding like terms, we get:-

-x^2 - 7x + 4   (answer).


6 0
3 years ago
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