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MariettaO [177]
3 years ago
9

The graph below shows three different normal distributions. 3 normal distributions are shown. They all peak at the same point, b

ut they all have different heights and widths. Which statement must be true?
A) Each distribution has a different mean and the same standard deviation.
B) Each distribution has a different mean and a different standard deviation.
C) Each distribution has the same mean and the same standard deviation.

D) Each distribution has the same mean and a different standard deviation.

Mathematics
2 answers:
yuradex [85]3 years ago
8 0

Answer:

D) Each distribution has the same mean and a different standard deviation.

Step-by-step explanation:

just took test edg2020

ella [17]3 years ago
7 0

Answer:

d

Step-by-step explanation:

edge 2020

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3 0
3 years ago
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Which of these numbers has the highest value? -22, 0.0099, 0, -1, (-1)
Oliga [24]
.0099 is the only positive number above zero and would have the highest value

5 0
3 years ago
x = c1 cos(t) + c2 sin(t) is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solution of the seco
igomit [66]

Answer:

x=-cos(t)+2sin(t)

Step-by-step explanation:

The problem is very simple, since they give us the solution from the start. However I will show you how they came to that solution:

A differential equation of the form:

a_n y^n +a_n_-_1y^{n-1}+...+a_1y'+a_oy=0

Will have a characteristic equation of the form:

a_n r^n +a_n_-_1r^{n-1}+...+a_1r+a_o=0

Where solutions r_1,r_2...,r_n are the roots from which the general solution can be found.

For real roots the solution is given by:

y(t)=c_1e^{r_1t} +c_2e^{r_2t}

For real repeated roots the solution is given by:

y(t)=c_1e^{rt} +c_2te^{rt}

For complex roots the solution is given by:

y(t)=c_1e^{\lambda t} cos(\mu t)+c_2e^{\lambda t} sin(\mu t)

Where:

r_1_,_2=\lambda \pm \mu i

Let's find the solution for x''+x=0 using the previous information:

The characteristic equation is:

r^{2} +1=0

So, the roots are given by:

r_1_,_2=0\pm \sqrt{-1} =\pm i

Therefore, the solution is:

x(t)=c_1cos(t)+c_2sin(t)

As you can see, is the same solution provided by the problem.

Moving on, let's find the derivative of x(t) in order to find the constants c_1 and c_2:

x'(t)=-c_1sin(t)+c_2cos(t)

Evaluating the initial conditions:

x(0)=-1\\\\-1=c_1cos(0)+c_2sin(0)\\\\-1=c_1

And

x'(0)=2\\\\2=-c_1sin(0)+c_2cos(0)\\\\2=c_2

Now we have found the value of the constants, the solution of the second-order IVP is:

x=-cos(t)+2sin(t)

3 0
3 years ago
Find the average rate of change over the given interval f(x)=3^x,[1,4]
nexus9112 [7]

Answer:

26

Step-by-step explanation:

Thus, f(b)−f(a)b−a=3(4)−(3(1))4−(1)=26.

7 0
3 years ago
How do you solve this equation 26x=74
Katyanochek1 [597]

Answer:

here is your answer in the picture..

8 0
3 years ago
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