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Zolol [24]
2 years ago
8

Sam is climbing 2/3 m every 15 minutes. How many meters will he climb in 1 hour?

Mathematics
2 answers:
Harrizon [31]2 years ago
7 0

Answer:

8/3 m

Step-by-step explanation:

1hr = 4*15min

2/3 * 4 = 8/3

Reika [66]2 years ago
5 0
He would claim 8/3 meters in a hour
You might be interested in
Solve the equation: k^2+5k+13=0
mr_godi [17]

Step-by-step explanation:

k² + 5k + 13 = 0

Using the quadratic formula which is

x =  \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}  \\

From the question

a = 1 , b = 5 , c = 13

So we have

k =  \frac{ - 5 \pm \sqrt{ {5}^{2} - 4(1)(13) } }{2(1)}  \\  =  \frac{ - 5 \pm \sqrt{25 - 52} }{2}  \\  =  \frac{ - 5 \pm \sqrt{ - 27} }{2}  \:  \:  \:  \:  \:  \:  \\  =  \frac{ - 5  \pm3 \sqrt{3}  \: i}{2}  \:  \:  \:  \:  \:  \:

<u>Separate the solutions</u>

k_1 =  \frac{ - 5 + 3 \sqrt{3} \: i }{2}  \:  \:  \:  \: or \\ k_2 =  \frac{ - 5 - 3 \sqrt{3}  \: i}{2}

The equation has complex roots

<u>Separate the real and imaginary parts</u>

We have the final answer as

k_1 =  -  \frac{5}{2}  +  \frac{3 \sqrt{3} }{2}  \: i \:  \:  \:  \: or \\ k_2 =  -  \frac{5}{2}  -  \frac{3 \sqrt{3} }{2}  \: i

Hope this helps you

8 0
2 years ago
288 times 66 =?<br> Plz help
gtnhenbr [62]
19,008 I just used a calculator
4 0
2 years ago
Read 2 more answers
Help giving extra points ASAP
Reika [66]
First of all you are going to want to google the way to solve that area of a triangle. Solve the triangles area. then find the area of the rectangle and add all of your answers to get the over all area.
6 0
3 years ago
0.8 rounded to nearest hundred
Tju [1.3M]

Answer:

1

Step-by-step explanation:

extending answer to be able to send

8 0
2 years ago
Read 2 more answers
A marketing researcher wants to find a 96% confidence interval for the mean amount those visitors spend per person per day while
ki77a [65]

Answer:

n=(\frac{2.054(12)}{4})^2 =37.97 \approx 38

So then the minimum sample to ensure the condition given is n= 38

Step-by-step explanation:

Notation

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=12 represent the population standard deviation

n represent the sample size  

ME = 4 the margin of error desired

Solution to the problem

When we create a confidence interval for the mean the margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =4 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 96% of confidence interval now can be founded using the normal distribution. The significance is \alpha=1-0.96 =0.04. And in excel we can use this formula to find it:"=-NORM.INV(0.02;0;1)", and we got z_{\alpha/2}=2.054, replacing into formula (b) we got:

n=(\frac{2.054(12)}{4})^2 =37.97 \approx 38

So then the minimum sample to ensure the condition given is n= 38

5 0
3 years ago
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