One reason that negative numbers would not make sense for values of the variables is that the solution having a negative value is not valid. It might be that the expression represents a real word problem and a negative value will not make any sense. Hope this helps.
Range is the outputs possible
w(r(x))=(2-x^2)-2
w(r(x))=2-x^2-2
w(r(x))=-x^2
therefor the range is from 0 to -∞
So easyies way is find all multiplues of 6 that are less than 50
6
12
18
24
30
36
42
48
and not 42
6
12
18
24
30
36
48
more than 25
30
35
48
do not have a 3 in them
48
the answer is 48
Answer:
C
Step-by-step explanation:
Well, anything multiplied by zero is zero.
If you multiplied 0 by 143, you wouldn't get anything because you're not multiplying with another number that can be multiplied by.
Point t slope form:
y + y value = m (x + x value) where m is the gradient
Parallel line must have the same gradient as the two lines never meet, so the gradient must be 4. This eliminates option B and D.
Remember that point-slope form is still an equation, so the values of both sides must be equal. So let's substitute the given coordinates.
Option A:
y-6=4(x+2)
-6-6 (-12) does not equal to 4(-2+2) (0)
Option C:
y+6=4(-2+2)
-6+6 (0) = 4(-2+2) (0)
Therefore, option C is your answer.