Given:
In a right angle triangle θ is an acute angle and
.
To find:
The value of
.
Solution:
In a right angle triangle,

We have,

It means the ratio of perpendicular to base is 3:5. Let 3x be the perpendicular and 5x be the base.
By using Pythagoras theorem,





In a right angle triangle,



Therefore, the value of
is
.
6+(-2)+2•(-8)•42=6-2+(-16)•42=4+(-672)=4-672=-668
I personally think Natalie's bill is the greatest because $24.25 × 10 =x
It would be B! :) have a good day