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Bumek [7]
3 years ago
8

Need help with equations with variables on both sides, giving 100 points, tysm if you help :) 6 (2x-4) = 8(x +2) A. 3 B. 10 C. 2

D. -2 3 (4p - 2) = -6 (1 - 2p) A. no solution B. all real numbers C. 0 D. -6 5 ( x- 2) = 3 (x + 6) -8 A. 10 B. 1 C. -1 D. 0 6 (2x-3) = - (x - 9) + 4x A. -6 B. -3 C. 9 D. 3
Mathematics
1 answer:
scoundrel [369]3 years ago
3 0

Answer:

B. 10

C. All real numbers.

Step-by-step explanation:

6 (2x-4) = 8(x + 2)

Distribute the numbers outside of the factors:

12x - 24 = 8x + 16

Subtract both sides by '8x'

12x - 8x - 24 = 8x - 8x + 16

4x - 24 = 16

Add '24' to both sides:

4x = 40

Divide both sides by 4:

x = 10. Therefore, <u>B. 10</u> is the correct answer.

3(4p - 2) = -6(1 - 2p)

Distribute the numbers similarly to the example before:

12p - 6 = -6 + 12p

Subtract '12p' from both sides:

12p - 12p -6 = -6 + 12p - 12p

0 -6 = -6

Add '6' to both sides:

0 - 6 + 6 = -6 + 6

0 = 0

Therefore, the solution consists of <u>all real numbers.</u>

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WILL AWARD BRAINLIEST ANSWER
Tpy6a [65]

Answer:

(x - 5)^2 + (y - 7)^2 = 13^2

or

(x - 5)^2 + (y - 7)^2 = 169

Step-by-step explanation:

Well, the center origin of the circle is given (h,k) =  (5,7).

We have to find our radius as they gave us a point. from origin to the edge of the circle.

Using the formula: (x - h)^2 + (y - k)^2 = r^2

Plug in our (h,k) = (5,7) and (x,y) =  (10,19) to solve for radius.

(x - h)^2 + (y - k)^2 = r^2

(10 - (5))^2 + (19 - (7)^2 = r^2

(5)^2 + (12)^2 = r^2

25 + 144  = r^2

r^2 = 169

r = 13

5 0
2 years ago
Complete the square to rewrite y = x^2 + 6x + 3 in vertex form. Then state whether the vertex is a maximum or a minimum and give
bixtya [17]

Answer:

Let's complete the square first.

y = x² + 6x + 3

  = (x² + 6x + 9) - 6

  = (x + 3)² - 6

Therefore, the vertex is (-3, -6) and since the coefficient of (x + 3)² is positive, the vertex is a minimum.

4 0
3 years ago
Read 2 more answers
A given line has the equation 10x + 2y = −2.
stepladder [879]
10x + 2y = -2

2y = -10x -2

y = -5x - 1 (slope is -5 and a parallel line will have the same slope)


y = mx + b

slope(m) = -5

12 = -5(0) + b

12 = 0 + b

12 = b

so the parallel line is y = -5x + 12

hope this helps, God bless!

3 0
3 years ago
I need help graphing 2x - 6y = 42 I'm just really lazy​
solong [7]

Answer:

We can use slope intercept form to get the points needed. Y= -7+1/3x The points are (0,-7) and (3,-6)

Step-by-step explanation:

Subtract 2x from the left side and place it over to the right side with the 42. Now we have -6y= 42-2x. From here we divide by -6 and we get y= -7+1/3x. We know that are slope is 1/3 which the one is the rise and the 3 is the run. We also know that our y intercept is -7. We plot the points at (0,-7) and (3,-6)

3 0
3 years ago
Expand the given power by using Pascal’s triangle. (9a - 10b)^6
xxMikexx [17]

Answer:

531441a^6-3542940a^5b+9841500a^4b^2-14580000a^3b^3+12150000a^2b^4-5400000ab^5+1000000b^6

Step-by-step explanation:

                     1                                n=0

                  1      1                            n=1

                 1   2   1                           n=2

                1  3  3  1                          n=3

              1  4  6  4   1                      n=4

             1  5 10 10 5  1                    n=5

           1 6 15 20 15 6 1                   n=6

This is where n is the exponent in

(x+y)^n.

(x+y)^6=1x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+1y^6

Now we want to expand:

(9a-10b)^6 or we we can rewrite as (9a+(-10b))^6.

Let's replace x with (9a) and y with (-10b) in the expansion:

(x+y)^6=1x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+1y^6

((9a)+(-10b))^6

=1(9a)^6+6(9a)^5(-10b)+15(9a)^4(-10b)^2+20(9a)^3(-10b)^3+15(9a)^2(-10b)^4+6(9a)(-10b)^5+1(-10b)^6

Let's simplify a bit:

=9^6a^6-60(9)^5a^5b+15(-10)^2(9)^4a^4b^2+20(9)^3(-10)^3a^3b^3+15(9)^2(-10)^4a^2b^4+6(9)(-10)^5ab^5+(-10)^6b^6

=531441a^6-3542940a^5b+9841500a^4b^2-14580000a^3b^3+12150000a^2b^4-5400000ab^5+1000000b^6

8 0
3 years ago
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