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bija089 [108]
3 years ago
5

Experimental Probability

Mathematics
1 answer:
Maslowich3 years ago
3 0
The fractions 2/18 and 1/9 are equivalent because the prior reduces to the latter. The first answer is correct, as instead of the four occurrences of the number two, Juan used the number two.  The correct fraction should have been 4/18. The number of occurrences over the number of times the dice was rolled, not 2/18, the quantity over the number of rolls. 
Hope this simplifies it, 
Ahawk
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What is the ratio of the intensities of an earthquake PP wave passing through the Earth and detected at two points 19 kmkm and 4
Tamiku [17]

Answer:

The ratio of the intensities is roughly 6:1.  

Step-by-step explanation:

The intensity I() of an earthquake wave is given by:

I = \frac{P}{4\pi d^{2}}

<em>where P: is the power ans d: is the distance. </em>

Hence, the ratio of the intensities of an earthquake wave passing through the Earth and detected at two points 19 km and 46 km from the source is:

\frac{I_{1}}{I_{2}} = \frac{P/4\pi d_{1}^{2}}{P/4\pi d_{2}^{2}}

<em>where I₁ = P/4πd₁², d₁=19 km, I₁ = P/4πd₂² and d₂=46 km     </em>

\frac{I_{1}}{I_{2}} = \frac{d_{2}^{2}}{d_{1}^{2}}

\frac{I_{1}}{I_{2}} = \frac{46 km^{2}}{19 km^{2}}

\frac{I_{1}}{I_{2}} = 5.9:1

Therefore, the ratio of the intensities is roughly 6:1.  

 

I hope it helps you!    

3 0
3 years ago
Suppose the height of an 18 year old boy is normally distributed with mean 187cm fifteen percent of 18 year old boys have height
BARSIC [14]

Answer:

the probability that two 18 year old boys chosen at random will have heights greater than 185cm is 0.403

Step-by-step explanation:

P( x > 193) = 0.15

= 1- p(x less than or equal 193)

= 1 -p( z < (x- u) /sigma)

= 1- p( z< (193 - 187)/ sigma)

= 1- p( z< 6/ sigma)

P(z< 6/sigma) = 1 - 0.15

P(z < 6/sigma)= 0.85

6/sigma =1.036

Sigma= 6/1.036

Sigma= 5.79

P( x> 185) = 1- p( x< 185)

= 1- p (z < (185- 187)/5.79)

= 1- p( z< -0.345)

= 1- 0.365

= 0.635

P (x> 185) = 0.635 × 0.635

=0.403

3 0
4 years ago
Carbon dioxide comprises approximately what percentage of the atmosphere
In-s [12.5K]

The Carbon Dioxide in the atmosphere is only very small relative to other gases. Typically, it only consists about 0.038 percent or 0.04 percent of the gases in the atmosphere.

<span>
Even though it is only small, CO2 is very important since it is one of the greenhouse gases which ensures that the Earth stays warm.</span>

8 0
3 years ago
Plzzzzzzzzzzzzzzzzzzzz Help me with this question
Akimi4 [234]
100 or the first one
5 0
3 years ago
Read 2 more answers
0.01 × 0.001<br>answer This​
WINSTONCH [101]

Answer:

0.00001

Step-by-step explanation:

6 0
3 years ago
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