Answer:
d.
Step-by-step explanation:
if x varies directly as y,
x = ky
8 = 12k
12k = 8
k = 8/ 12
k = 2/3,
x = 2/3 y
now substitute the value of any of the numbers of each pair, and check if it works:
for e.g, find x when y = 15
x = 2/3y
x = 2/3 × 15
x = 10
since you obtain x = 10 when y = 15, the pair is a possible corresponding value of x and y. now do the same for the rest .
ii) x = 2/3y
x = 2/3 × 3, when y = 3
x = 2
hence, this is also a possible pair of x and y values.
iii) x = 2/3y
x = 2/3 × 9 when y = 9
x = 6
again, a possible pair of x and y values.
iv) x = 2/3y
x = 2/3 × 20 when y = 20
x = 40/3
here, when y = 20, x is not 15. it is 40/3.
thus, it can be determined that this is not a possible pair of x and y values.
please try to understand and have a great day!
Answer: 0.58 m^3
Step-by-step explanation:
V= 2600 / 1500
= 0.58 m^3
Answer:
x = 5
Please tell me if im incorrect and hope this helped ^^
A. The equation to find the distance of the flowerbed from the hive is:
, where x is the distance.
B. The flowerbed is 2250 feet far from the hive.
<u><em>Explanation</em></u>
Suppose, the distance of the flowerbed from the hive is
feet.
The bee flies 20 feet per second directly to a flowerbed from its hive and flies directly back to the hive at 12 feet per second.
As,
So, the time taken by the bee to reach the flowerbed
seconds and the time taken to fly back to the hive
seconds.
The bee stays at the flowerbed for 15 minutes or (15×60)seconds or 900 seconds and it is away from the hive for a total of 20 minutes or (20×60)seconds or 1200 seconds.
So, the equation will be.......

Thus, the distance of the flowerbed from the hive is 2250 feet.
Answer:
(x+2)(3x+1)
Step-by-step explanation: