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rosijanka [135]
3 years ago
13

A.75/1 dollars per daythe cost $75 for each day.

Mathematics
2 answers:
Rama09 [41]3 years ago
5 0

Answer:

D

Step-by-step explanation:

Count by 25. Its a no-brainer honestly.

NISA [10]3 years ago
3 0
D cause it can be and it’s the easy way to do it I’m not gonna lie to you
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Find the missing dimension of the cylinder. round your answer to the nearest whole number
Ulleksa [173]

Answer:

11 meters

Step-by-step explanation:

Use the formula:

V = \pi r^{2} h

V = 7599, h = 20, π = 3.14

Plugin the numbers and solve for r

7599=3.14(20)r^{2} \\7599=62.8r^{2} \\7599/62.5=62.8r^{2} /62.8\\121=r^{2} \\\sqrt{121}=\sqrt{r^{2} } \\r=11

8 0
2 years ago
Susie is visiting China from the U.S. One day she stopped by a market and found a stall selling tomatoes for 15.65 yuan per kilo
liq [111]

Answer:

1st blank is 0,14 dollars/1yuan, and 2nd blank is 1kg/2.2lb

Step-by-step explanation:


5 0
4 years ago
Two random samples were taken to determine how often people in a community listen to the local radio station each month.
Dvinal [7]

Answer:

1 2 4 6. Tell me if im wrong.

Step-by-step explanation:

7 0
3 years ago
Determine the area of each semicircle or quarter circle. Think carefully about whether the length you are given corresponds to a
VashaNatasha [74]

Answer:

Area of semicircle = 1/2(πr^2)

Area of quarter circle = 1/4(πr^2)

Step-by-step explanation:

The question is incomplete. You didn't provide the diagrams for the semicircle and quarter circle to evaluate the areas. I would explain how to find the area of a semicircle and quarter circle.

Area of a circle = πr^2

where r = radius and π = 3.14

If diameter (d) is given: d = 2r

To get radius, divide diameter by 2.

r = d/2

A semicircle is half of a circle.

Area of a semicircle is half the area of a circle.

Area of a semicircle = 1/2(πr^2)

A quarter circle is a quarter of a circle.

Area of a quarter circle is quarter of the area of a circle.

Area of a quarter circle = 1/4(πr^2)

Further explanation with diagram has been added as as an attachment.

6 0
4 years ago
Qual o valor que Z assume?<br> -Cz+ 6z = Tz+ 83
o-na [289]

Answer:

\large \boxed{z = \dfrac{83}{6 - C - T}}

Step-by-step explanation:

\begin{array}{rccl}-Cz + 6z & = & Tz + 83 & \\6z -Cz - Tz &= & 83 & \text{Subtracted Tz from each side}\\z(6 - C - T)  & = & 83 & \text{Removed the common factor}\\z& = & \mathbf{\dfrac{83}{6 - C - T}} &\text{Divided each side by 6 - C - T}\\\end{array}\\\\\large \boxed{\mathbf{z = \dfrac{83}{6 - C - T}}}

3 0
3 years ago
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