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ad-work [718]
3 years ago
13

Imagine deleting everything i put

Mathematics
1 answer:
NARA [144]3 years ago
5 0

Answer:

oof that's gotta suck bro

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Give the correct answer<br>Solve all questions to get brainliest
beks73 [17]

Let me translate it to English before I answer your question.

Hello friend, how are you? Today I want to write about my schedule of classes.

My classes start at seven thirty in the morning. I have five classes everyday. My math class, it starts at seven thirty. Then a biology class and it starts at half past nine. I have a twenty minute break at noon. It starts at half past seven. I always have soccer practice after school, but today I have to come home early because I have to study for the biology test. Take care.

First answer: 20 mins

Second answer: 7:30

Third answer:7:30

Fourth answer:9:05

Hope this helps you!!

Stay safe.

5 0
3 years ago
Use Newton’s method to approximate the indicated root of the equation correct to six decimal places. The positive root of 3 sin
MAXImum [283]

Answer:

x \approx 2.278863

Step-by-step explanation:

Required

The positive root of 3\sin(x) = x

Equate to 0

0 = x -3\sin(x)

So, we have our function to be:

h(x) = x -3\sin(x)

Differentiate the above function:

h'(x) = 1 -3\cos(x)

Using Newton's method of approximation, we have:

x_{n+1} = x_n - \frac{h(x_n)}{h'(x_n)}

Plot the graph of h(x) = x -3\sin(x) to get x_1 --- see attachment for graph

From the attached graph, the first value of x is at 2.2; so:

x_1 = 2.2

So, we have:

x_{n+1} = x_n - \frac{h(x_n)}{h'(x_n)}

x_{1+1} = x_1 - \frac{h(x_1)}{h'(x_1)}

x_{2} = 2.2 - \frac{2.2 -3\sin(2.2)}{1 -3\cos(2.2)} = 2.28153641

The process will be repeated until the digit in the 6th decimal place remains unchanged

x_{3} = 2.28153641 - \frac{2.28153641 -3\sin(2.28153641)}{1 -3\cos(2.28153641)} = 2.2788654

x_{4} = 2.2788654 - \frac{2.2788654 -3\sin(2.2788654)}{1 -3\cos(2.2788654)} = 2.2788627

x_{5} = 2.2788627 - \frac{2.2788627-3\sin(2.2788627)}{1 -3\cos(2.2788627)} = 2.2788627

Hence:

x \approx 2.278863

4 0
3 years ago
A regression equation is determined that describes the relationship between average January temperature (degrees Fahrenheit) and
Musya8 [376]

Answer:

Decreases by 2 degrees

Step-by-step explanation:

The expression that describes temperature as a function of latitude is:

T=110-2(Latitude)

This equation represents a linear relationship between latitude and temperature in a way that an increase in latitude causes a decrease in temperature. The magnitude of this decrease is quantified by the slope of the linear equation, which is -2. Therefore, the estimated temperature decreases by 2 degrees when latitude is increased by one.

8 0
3 years ago
Help me? shhhhh.....its for a test
Lena [83]

Answer:

1/5

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Consider the numbers √27 and √39.
kobusy [5.1K]
√27 = 5.2 (to 1 dp)
√39 = 6.2 (to 1 dp)
A. √39 is greater.
B. 6 is the only whole number between the two.
Hope this helped :)
3 0
3 years ago
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