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Usimov [2.4K]
3 years ago
14

Need help I got not time to do all the work and is almost due

Mathematics
2 answers:
xxMikexx [17]3 years ago
8 0

Answer:

13-5=2m

8=2m

m=8÷2

hence m=4

Tatiana [17]3 years ago
8 0

Answer:

m = 4

Step-by-step explanation:

my work is included in the picture :)

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Where is 11/3 on a number line between 2 and 4
lions [1.4K]
Hiii! To work it out, you would have to do 11 ÷ 3. Which would equal 3.6 (Recurring).  If it's to one decimal place, it would be 4 if not, it would just be 3.6 ^^

Hope it helps!! Good luck~
7 0
3 years ago
If your car goes 50 kilometers in 2 hours,what is its average speed
Georgia [21]

Answer:

25 kilometers per hour

Step-by-step explanation:

I just simply made it into a proportion of 50/2=x/1 and 50 divided by 2 is 25. hopefully that help you.

8 0
3 years ago
what is The ratio of boys to girls at the dance was 9 to 5. How many girls were at the dance if there were 85 girls at the dance
AleksandrR [38]

Answer: 153 boys

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Select one:<br><br> A. 7<br> B. 0 (INCORRECT)<br> C. (12,-5) <br> D. (2,3) (INCORRECT)
Veronika [31]
I got A for the answer
plz mark brainliest

8 0
3 years ago
Read 2 more answers
(a) Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the prop
zalisa [80]

Answer:

(a) The sample sizes are 6787.

(b) The sample sizes are 6666.

Step-by-step explanation:

(a)

The information provided is:

Confidence level = 98%

MOE = 0.02

n₁ = n₂ = n

\hat p_{1} = \hat p_{2} = \hat p = 0.50\ (\text{Assume})

Compute the sample sizes as follows:

MOE=z_{\alpha/2}\times\sqrt{\frac{2\times\hat p(1-\hat p)}{n}

       n=\frac{2\times\hat p(1-\hat p)\times (z_{\alpha/2})^{2}}{MOE^{2}}

          =\frac{2\times0.50(1-0.50)\times (2.33)^{2}}{0.02^{2}}\\\\=6786.125\\\\\approx 6787

Thus, the sample sizes are 6787.

(b)

Now it is provided that:

\hat p_{1}=0.45\\\hat p_{2}=0.58

Compute the sample size as follows:

MOE=z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})}{n}

       n=\frac{(z_{\alpha/2})^{2}\times [\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})]}{MOE^{2}}

          =\frac{2.33^{2}\times [0.45(1-0.45)+0.58(1-0.58)]}{0.02^{2}}\\\\=6665.331975\\\\\approx 6666

Thus, the sample sizes are 6666.

7 0
2 years ago
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