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Yes, it is continuous to its domain
<h2>Explanation:</h2><h2></h2>In order to find the domain of the function we need to get the restrictions:
1. From natural log:
2. From quotient:
Matching these two restrictions the domain is:
So the function is continuous to its domain because is defined for every x-value in the interval )
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Given that there is no any option to choose I am going to help you according to the concepts of Congruent Triangles. Two triangles are congruent if and only if:
1. They have:exactly the same three sides
2. exactly the same three angles.
<span>There are five ways to find if two triangles are congruent but in this problem we will use only two.
First Answer:
<u>ASA criterion:</u> </span><em>A</em><span><em>ngle, side, angle</em>. This means that we have two triangles where we know two angles and the included side are equal.</span>
So:
If ∠BAC = ∠DEF and
<em>Then ΔABC and ΔEFD are congruent by ASA criterion.</em>
Second answer:
<u>SAS criterion:</u> <em>S</em><span><em>ide, angle, side</em>. This means that we have two triangles where we know two sides and the included angle are equal.
</span>
<em>Then ΔABC and ΔEFD are congruent by SAS criterion.</em>
1. They have:exactly the same three sides
2. exactly the same three angles.
<span>There are five ways to find if two triangles are congruent but in this problem we will use only two.
First Answer:
<u>ASA criterion:</u> </span><em>A</em><span><em>ngle, side, angle</em>. This means that we have two triangles where we know two angles and the included side are equal.</span>
So:
If ∠BAC = ∠DEF and
<em>Then ΔABC and ΔEFD are congruent by ASA criterion.</em>
Second answer:
<u>SAS criterion:</u> <em>S</em><span><em>ide, angle, side</em>. This means that we have two triangles where we know two sides and the included angle are equal.
</span>
<em>Then ΔABC and ΔEFD are congruent by SAS criterion.</em>