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Sloan [31]
2 years ago
13

Find the perimeter and area of the following

Mathematics
1 answer:
elena55 [62]2 years ago
3 0

16. PM = 26x + 8x^2y

A = 52x^3y

17. Area = 33a^5b

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9 units

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(0,7)-(-2,-2)= (2,9)

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Evaluate (3)^1/6 × (3)^-2/3
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7. Use the properties of operations to simplify this algebraic expression. Rewrite the expression by following the directions in
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3 0
3 years ago
The upper-left coordinates on a rectangle are (-6,0)(−6,0)left parenthesis, minus, 6, comma, 0, right parenthesis, and the upper
nikklg [1K]

Answer:

See attachment for rectangle

Step-by-step explanation:

Given

A = (-6,0)

B = (-4,0)

Area = 12

Required

Draw the rectangle

First, we calculate the distance between A and B using distance formula;

AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}

So, we have:

AB = \sqrt{(-6 - -4)^2 + (0- 0)^2}

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AB = \sqrt{4 + 0}

AB = \sqrt{4}

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Next, calculate the width using:

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This implies that, the width of the rectangle is 6 units.

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A = (-6,0)

B = (-4,0)

Since A and B are at the upper left and right, then the ther two points are below.

6 units below each of the above point are:

C = (-6,0-6)\\ => C = (-6,-6)

D = (-4,0-6) => D = (-4,-6)

Hence, the points of the rectangle are:

A = (-6,0)

B = (-4,0)

C = (-6,-6)

D = (-4,-6)

<em>See attachment for rectangle</em>

6 0
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