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3 years ago

Help me please I think you have to find the area

Mathematics

1 answer:

abruzzese [7]3 years ago

8 0

Answer:

I got B) ; 54m2

Step-by-step explanation:

the above diagram is a trapezium.

the area is gotten by; 1/2 (a+b)h

a = shortest side.

b = the longer side that is directly opposite to (a).

h = height.

1/2(3 + 9)9

1/2 by 12 by 9

to get 54

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What is the messure of N and the two angles; an-16 and 6n

AURORKA [14]

Answer:

14, 96,84

Step-by-step explanation:

8n - 16 + 6n = 180 {Supplementary angles}

<u>8n + 6n</u> -16 = 180

Combine like terms

14n - 16 = 180

Add 16 to both sides

14n = 180 + 16

14n = 196

Divide both sides by 14

n = 196/14

n = 14

8n - 16 = 8*14 - 16 = 112 - 16 = 96

6n = 6 *14 = 84

7 0

3 years ago

So I know I ask a lot of questions but I really don't know this one

Tresset [83]

A & C are the Answer

7 0

3 years ago

Homework, 12 points for whoever answers.

adell [148]

The answer to number 1 = 40

5 0

3 years ago

Read 2 more answers

A cylindrical rain barrel has a radius of 2 feet and holds a total of 30 cubic feet of water. How tall is the rain barrel? Use 3

enot [183]

Answer:

2.39 feet

Step-by-step explanation:

we know that

The volume of a cylinder is equal to

$V=\pi r^{2}h$

where

r is the radius of the base of the cylinder

h is the height of the cylinder

we have

$V=30\ ft^3$

$r=2\ ft$

$\pi =3.14$

substitute

$30=(3.14)(2^{2})h$

Solve for h

$30=(3.14)(4)h$

$h=30/12.56$

$h=2.39\ ft$

7 0

3 years ago

A volleyball reaches its maximum of 13 feet, 3 seconds after it is served. What quadratic formula could model the height of the

Katena32 [7]

Answer:

$H=-(t-3)^2+13$

Step-by-step explanation:

The path covered by the volleyball will be a downward parabola with the vertex being the highest point of the ball.

A general form of a downward parabola is given as:

$y=-a(x-h)^2+k$

Where $(h,k)$ is the vertex of the parabola and 'a' is a constant.

Now, let 'h' be the vertical height and 't' be the time taken.

So, the equation would be of the form:

$H=-a(t-h)^2+k$

Now, as per question:

h = 2 seconds, k = 13 feet.

$H=-a(t-3)^2+13$

Now, taking a = 1. So, the formula that can be used is:

$H=-(t-3)^2+13$

7 0

3 years ago