Research what is something times something equals 43

HELP ASAPP!!!Select the correct answer.

alex41 [277]

Answer:

B. r=C/2pi

Step-by-step explanation:

C=2piR

C/2pi=R

3 0

3 years ago

Read 2 more answers

If the life in years of a television set is normally distributed with a mean of 36 years and a standard deviation of 8 years wha

TiliK225 [7]

Answer:

The company should guarantee a lifetime of less than equal to 20.95 years so that less than 3% of the television sets fail while under warranty.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 36 years

Standard Deviation, σ = 8 years

We are given that the distribution of life of television sets is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

We have to find the value of x such that the probability is 0.03.

$P( X < x) = P( z < \displaystyle\frac{x - 36}{8})=0.03$

Calculation the value from standard normal z table, we have,

$\displaystyle\frac{x - 36}{8} =-1.881\\\\x = 20.952\approx 20.95$

Thus, the company should guarantee a lifetime of less than or equal to 20.95 years so that less than 3% of the television sets fail while under warranty.

3 0

3 years ago

Due to a packaging error, 4 cans labeled diet soda were accidentally filled with regular soda and placed in a 12 pack carton of

Sophie [7]

Answer:

Probability that both cans were regular soda = $\frac{1}{11}$

Step-by-step explanation:

Probability = $\frac{Desired outcome}{Total possible outcomes}$

We are given 12 total number of cans; 4 cans have been accidentally filled with diet soda.

Probability that first can is a regular soda:

Outcome that first can is a regular soda will give us the number of regular soda available which are 4

Using formula of probability

Total possible outcomes are, n(total) = 12

Desired outcome: 4 (cans of regular soda)

P(1st can) = $\frac{4}{12}$ = $\frac{1}{3}$

Probability that 2nd can is a regular soda:

<em>As we have already taken a can of regular soda from the pack, the total soda in the pack now 11 and the regular soda left are 3.</em>

Total possible outcomes are, n(total) = 11

Desired outcome: 3 (cans of regular soda as one has already been taken)

P(2nd can) = $\frac{3}{11}$

Probability that both cans are regular soda:

P(both) = P(1st can) × P(2nd can)

= $\frac{1}{3} * \frac{3}{11}$

= $\frac{1}{11}$

3 0

3 years ago

Read 2 more answers

Solve the system by graphing. Select the solution(s).<br> y = x + 2<br> y = 0.5(x + 2)

faltersainse [42]

Answer:

Part 1) The solution is the point (-2,0)

Part 2) The solutions are the points (-2,0) and (0,2)

Step-by-step explanation:

Part 1

we have

$y=x+2$ -----> equation A

$y=0.5(x+2)$ ----> $y=0.5x+1$ ---> equation B

Solve the system by graphing

Remember that the solution of the system is the intersection point both graphs

using a graphing tool

The solution is the point (-2,0)

see the attached figure N 1

Part 2

we have

$y=x+2$ -----> equation A

$y=0.5(x+2)^2$ ----> equation B

Solve the system by graphing

Remember that the solution of the system are the intersection points both graphs

using a graphing tool

The solutions are the points (-2,0) and (0,2)

see the attached figure N 2

4 0

3 years ago

Find a number C such that the polynomial p(x)= -x+4x^2+Cx^3-8x^4

Ksenya-84 [330]

Answer:

C = 2

Step-by-step explanation:

$p(x)= -x+4x^2+Cx^3-8x^4 \\ \\ \because \: given \: polynmial \: has \: zero \: at \: \\x = \frac{1}{4} \\ \\ \implies \: p\bigg(\frac{1}{4} \bigg) = 0...(1) \\ \\ plug \: x = \frac{1}{4} \: in \: p(x) \: we \: find \\ \\ p \bigg(\frac{1}{4} \bigg) = - \frac{1}{4} + 4 {\bigg(\frac{1}{4} \bigg)}^{2} + c {\bigg(\frac{1}{4} \bigg)}^{3} - 8 {\bigg(\frac{1}{4} \bigg)}^{4} \\ \\ 0 = - \frac{1}{4} + \cancel 4 \times {\frac{1}{\cancel{16} } } + c {\bigg(\frac{1}{64} \bigg)} - \cancel 8 \times \frac{1}{\cancel{256} } \\ \\0 =\cancel{ - \frac{1}{4}} + \cancel {{\frac{1}{4} }} + c {\bigg(\frac{1}{64} \bigg)} - \times \frac{1}{32} \\ \\0 = c {\bigg(\frac{1}{64} \bigg)} - \frac{1}{32} \\ \\c {\bigg(\frac{1}{64} \bigg)} = \frac{1}{32} \\ \\ c = \frac{1}{32} \times 64 \\ \\ c = 2$

5 0

3 years ago