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3 years ago

What is the value for y in the following equation when x = -10?

Mathematics

1 answer:

nadezda [96]3 years ago

6 0

Answer:

B.-38

Step-by-step explanation:

2x - 18 = y ...(1)

x = -10 (Given)

Now,

Put the value of x in equation (1) we get,

2(-10) - 18 = y

-20 - 18 = y

-38 = y

<em><u>y = -38</u></em>

Thus, the value of y is -38

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A round table has 4 legs and a rectangular table has 6 legs. If 10 tables have a total of 52 legs, how many of the legs belong t

ivolga24 [154]

Answer:

16 because if each chair has 4 legs you multiply that by the amount of chairs you have. 4x4=16

Step-by-step explanation:

4x4=16

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2 years ago

Which of the following represents the zeros of f(x) = 2x3 − 5x2 − 28x + 15?

likoan [24]

$\mathrm{Use\:the\:rational\:root\:theorem}$

$a_0=15,\:\quad a_n=2$

$\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:3,\:5,\:15,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1,\:2$

$\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:3,\:5,\:15}{1,\:2}$

$-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3$

$\mathrm{Compute\:}\frac{2x^3-5x^2-28x+15}{x+3}\mathrm{\:to\:get\:the\:rest\:of\:the\:eqution:\quad }2x^2-11x+5$

$=\left(x+3\right)\left(2x^2-11x+5\right)$

$Factor: 2x^2-11x+5$

$2x^2-11x+5=\left(2x^2-x\right)+\left(-10x+5\right)$

$=x\left(2x-1\right)-5\left(2x-1\right)$

$2x^3-5x^2-28x+15=\left(x+3\right)\left(x-5\right)\left(2x-1\right)$

$\left(x+3\right)\left(x-5\right)\left(2x-1\right)=0$

$\mathrm{Using\:the\:Zero\:Factor\:Principle:}$

thus zeros of f(x) is

$x=-3,\:x=5,\:x=\frac{1}{2}$

5 0

3 years ago

Read 2 more answers

A new shopping mall records 120 total shoppers on their first day of business. Each day after that, the number of shoppers is 10

Iteru [2.4K]

Answer:

$1,139\ shoppers$

Step-by-step explanation:

we know that

In this problem we have a exponential function of the form

$y=a(b)^{x}$

where

a is the initial value or y-intercept

b is the base of the exponential function

r is the rate in decimal form

b=(1+r)

In this problem we have

x ----> the number of days

y ----> the number of shoppers

a=120

r=10%=10/100=0.10

b=1+0.10=1.10

substitute the values

$y=120(1.10)^{x}$

First day

$y=120$

Second day

For x=1 day

substitute the value of x in the equation and solve for y

$y=120(1.10)^{1}=132$

Third day

For x=2 days

$y=120(1.10)^{2}=145$

Fourth day

For x=3 days

$y=120(1.10)^{3}=160$

Fifth day

For x=4 days

$y=120(1.10)^{4}=176$

Sixth day

For x=5 days

$y=120(1.10)^{5}=193$

Seventh day

For x=6 days

$y=120(1.10)^{6}=213$

Adds the numbers

$120+132+145+160+176+193+213=1,139$

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3 years ago

Read 2 more answers

Describe a real-life multiplication situation for which an estimate makes sense

Darya [45]

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5 0

3 years ago

9. 85 x s; s = 4 please help

Arisa [49]

Answer: 9.85 == 4 = False

Step-by-step explanation: its cant equal the same answer other its odd or even I think whats the answer(I Think that what the question meant....)

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3 years ago