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Andrew [12]
3 years ago
10

40% of ? =240 can anybody slove it​

Mathematics
2 answers:
Sav [38]3 years ago
7 0

I am not sure about the answer.

vovangra [49]3 years ago
5 0

Answer: 600

Step-by-step explanation: Let's first rewrite this problem to say 40% of what number is 240.

To answer the question 40% of what number is 240, we translate the question into an equation. First we have 40% which we need to write as a decimal. To write 40% as a decimal, we move the decimal point 2 places to the left. Filling in the missing position with a zero, we get 0<em>.</em>4.

Next we have "of what number" which means times <em>x</em>, "is 240" equals 240.

Now we have the equation (0.40)(x) = 240.

Now to solve for <em>x</em>, since <em>x</em> is being multiplied by 0.40, we need to divide by 0.40 on both sides of the equation. On the left side of the equation the 0.40's cancel and we have <em>x</em>. On the right side of the equation we have 240 divided by 0.40 which is 600.

This means that x = 600.

This means that 40% of 600 is 250.

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Custom Office makes a line of executive desks. It is estimated that the total cost for making x units of their Senior Executive
Ivan

Answer:

(a) The average cost function is \bar{C}(x)=95+\frac{230000}{x}

(b) The marginal average cost function is \bar{C}'(x)=-\frac{230000}{x^2}

(c) The average cost approaches to 95 if the production level is very high.

Step-by-step explanation:

(a) Suppose C(x) is a total cost function. Then the average cost function, denoted by \bar{C}(x), is

\frac{C(x)}{x}

We know that the total cost for making x units of their Senior Executive model is given by the function

C(x) = 95x + 230000

The average cost function is

\bar{C}(x)=\frac{C(x)}{x}=\frac{95x + 230000}{x} \\\bar{C}(x)=95+\frac{230000}{x}

(b) The derivative \bar{C}'(x) of the average cost function, called the marginal average cost function, measures the rate of change of the average cost function with respect to the number of units produced.

The marginal average cost function is

\bar{C}'(x)=\frac{d}{dx}\left(95+\frac{230000}{x}\right)\\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g\\\\\frac{d}{dx}\left(95\right)+\frac{d}{dx}\left(\frac{230000}{x}\right)\\\\\bar{C}'(x)=-\frac{230000}{x^2}

(c) The average cost approaches to 95 if the production level is very high.

\lim_{x \to \infty} (\bar{C}(x))=\lim_{x \to \infty} (95+\frac{230000}{x})\\\\\lim _{x\to a}\left[f\left(x\right)\pm g\left(x\right)\right]=\lim _{x\to a}f\left(x\right)\pm \lim _{x\to a}g\left(x\right)\\\\=\lim _{x\to \infty \:}\left(95\right)+\lim _{x\to \infty \:}\left(\frac{230000}{x}\right)\\\\\lim _{x\to a}c=c\\\lim _{x\to \infty \:}\left(95\right)=95\\\\\mathrm{Apply\:Infinity\:Property:}\:\lim _{x\to \infty }\left(\frac{c}{x^a}\right)=0\\\lim_{x \to \infty} (\frac{230000}{x} )=0

\lim_{x \to \infty} (\bar{C}(x))=\lim_{x \to \infty} (95+\frac{230000}{x})= 95

6 0
3 years ago
5x-4=-3-x so ya can yall help
Ket [755]

Step-by-step explanation:

5x-4=-3-x

5x+x=4+(-3)

6x=1

x=1/6

4 0
3 years ago
Read 2 more answers
Mark ran 875 miles this year in the track club.Mark ran in 52 track meets and ran the same number of miles in each.How many mile
shepuryov [24]

Answer:

The number of miles Mark runs in each track be 16 \frac{43}{52}\ miles

Step-by-step explanation:

Let us assume that the number of miles Mark run in each track meet be x.

As given

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Mark ran in 52 track meets and ran the same number of miles in each.

Than the equation becomes

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x = \frac{875}{52}

x = 16 \frac{43}{52}\ miles

Therefore the number of miles Mark runs in each track be 16 \frac{43}{52}\ miles

7 0
3 years ago
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Answer:

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stepladder [879]

Answer:

false

Step-by-step explanation:

these measure do not form a right triangle

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