Givens
x + y = 3
x =6 - 4y
Solution
Use the top equation to substitute for x in the second equation.
x = 3 - y
Put this result into the second given equation and solve for y
3 - y = 6 - 4y Add 4y to both sides.
3 - y + 4y = 6 Combine on the left
3 + 3y = 6 Subtract 3 from both sides
3 - 3 + 3y = 6 - 3 Combine
3y = 3 Divide by 3
3y/3 = 3/3 Combine
y = 1
=========================
x + y = 3 but y = 1
x + 1 = 3 Subtract 1 from both sides.
x + 1 - 1 =3 - 1
x = 2
Answer
x = 2
y = 1
Answer:
In the form of
Y= mx+c
Y= 1/2x +2
m = 1/2
Step-by-step explanation:
A linear equation in it's standard form is in the format
Y= mx+c
Where m is the slope and c is the y intercept
Let's use these two points to determine both the slope and the equation
(2, 3), (4,4)
Slope= (y2-y1)/(x2-x1)
Slope= (4-3)/(4-2)
Slope= 1/2
Equation of the linear function
(Y-y1)/(x-x1)= m
(Y-3)/(x-2)= 1/2
2(y-3) = x-2
2y -6 = x-2
2y= x-2+6
2y= x+4
Y= 1/2x +2
Is it 100 because it just is done ya and 1000
Answer:
Step-by-step explanation:
You already highlighted the term coordinate ratio in purple.
<h3>
Answer: Check out the diagram below.</h3>
Explanation:
Use your straightedge to extend segment AB into ray AB. This means you'll have it start at A and go on forever through B. Repeat these steps to turn segment AC into ray AC.
The two rays join at the vertex angle A. Point A is the center of the universe so to speak because it's the center of dilation. We consider it an invariant point that doesn't move. Everything else will move. In this case, everything will move twice as much compared to as before.
Use your compass to measure the width of AB. We don't need the actual number. We just need the compass to be as wide from A to B. Keep your compass at this width and move the non-pencil part to point B. Then mark a small arc along ray AB. What we've just done is constructed a congruent copy of segment AB. In other words, we've just double AB into AB'. This means the arc marking places point B' as the diagram indicates.
The same set of steps will have us construct point C' as well. AC doubles to AC'
Once we determine the locations of B' and C', we can then form triangle A'B'C' which is an enlarged copy of triangle ABC. Each side of the larger triangle has side lengths twice as long.
Note: Points A and A' occupy the same exact location. As mentioned earlier, point A doesn't move.