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Vaselesa [24]
3 years ago
9

Write a decimal where the value of a digit is 1/10 as much as a digit in another place.

Mathematics
1 answer:
dolphi86 [110]3 years ago
6 0

<span>10.1,  20.1  , 30.1 are the decimal where the value of digit 1/10 had existed.</span>

<span>“Decimal” comes from the Latin root decem, which simply means “ten.” The number system we use is called the decimal number system, because the place value units go in tens: you have ones, tens, hundreds, thousands, and so on, each unit being 10 times the previous one.</span>

 

In common language, the word “decimal number” has come to mean numbers which have digits after the decimal point, such as 5.8 or 9.302. But any number within the decimal number system could be designate a decimal number, involve whole numbers such as 12 or 381.

<span>A Decimal Number (<span>based on the number 10</span>) contains a Decimal Point.</span>

<span>Here is the number "forty-five and six-tenths" written as a decimal number:</span>

The decimal point goes between Ones and Tenths.

45.6 has 4 Tens, 5 Ones and 6 Tenths, like this:<span>40+5+6/10</span>

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The CEO of a large manufacturing company is curious if there is a difference in productivity level of her warehouse employees ba
blsea [12.9K]

Answer:

The test statistic is z = -2.11.

Step-by-step explanation:

Before finding the test statistic, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Group 1: Sample of 35, mean of 1276, standard deviation of 347.

This means that:

\mu_1 = 1276, s_1 = \frac{347}{\sqrt{35}} = 58.6537

Group 2: Sample of 35, mean of 1439, standard deviation of 298.

This means that:

\mu_2 = 1439, s_2 = \frac{298}{\sqrt{35}} = 50.3712

Test if there is a difference in productivity level.

At the null hypothesis, we test that there is no difference, that is, the subtraction is 0. So

H_0: \mu_1 - \mu_2 = 0

At the alternate hypothesis, we test that there is difference, that is, the subtraction is different of 0. So

H_1: \mu_1 - \mu_2 \neq 0

The test statistic is:

z = \frac{X - \mu}{s}

In which X is the sample mean, \mu is the value tested at the null hypothesis and s is the standard error.

0 is tested at the null hypothesis:

This means that \mu = 0

From the two samples:

X = \mu_1 - \mu_2 = 1276 - 1439 = -163

s = \sqrt{s_1^2+s_2^2} = \sqrt{58.6537^2+50.3712^2} = 77.3144

Test statistic:

z = \frac{X - \mu}{s}

z = \frac{-163 - 0}{77.3144}

z = -2.11

The test statistic is z = -2.11.

7 0
3 years ago
Replace ∗ with a monomial so that the derived equality will be an identity: (15y + ∗)2 = 225y2+12x3y+0.16x6
kobusy [5.1K]

Answer:

<u>∗ = 0.4x³</u>

Step-by-step explanation:

(15y + ∗)² = 225y²+12x³y+0.16x⁶

<u>Note:</u>

225y² = 15y * 15y = (15y)²

12x³y = 2 * 15y * 0.4x³

0.16x⁶ = 0.4x³ * 0.4x³ = (0.4x³)²

So, by factoring the right hand side:

225y²+12x³y+0.16x⁶ = (15y + 0.4x³)²

By comparing the left hand side with (15y + 0.4x³)²

<u>So, ∗ should be replaced with the monomial 0.4x³</u>

6 0
3 years ago
If the ratio of dogs to cats at an animal shelter is 2:5, then the number of cats is _____ times the number of dogs.
saul85 [17]
So 2:5 means that 5/7 animals are cats and 2/7 are dogs. I believe if you divide u will get your answer. 5/7 * 7/2 = 1.25x the number of dogs
6 0
3 years ago
In January Jennifer was allowed to use 150 text messages. If she is allowed to use the same amount of text messages every month.
Firlakuza [10]

She would have used 1200 messages in all by the month of August.

Step-by-step explanation:

Messages allowed per month = 150

There will be 8 months starting from January to August, therefore,

Time period = 8 months

Messages in 8 months = Messages per month * Time period

Messages\ in\ 8\ months=150*8\\Messages\ in\ 8\ months=1200

She would have used 1200 messages in all by the month of August.

Keywords: Multiplication

Learn more about multiplication at:

  • brainly.com/question/629998
  • brainly.com/question/6208262

#LearnwithBrainly

6 0
3 years ago
Hurry please! The table shows the results of a survey about favorite movie theater snacks.Write a fraction in simplest form that
Basile [38]
So if 24 people chose popcorn and there is a total of 60 people surveyed, the fraction would be 24/60. You still need to simplify the fraction, so divide 24/60 by 4 to get 6/15. Hope this helps. -S
4 0
4 years ago
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