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levacccp [35]
3 years ago
8

What is the GCF of the expression 6(x^3)(y^3)+45(x^2)(y^2)+21xy? * Your answer

Mathematics
1 answer:
arlik [135]3 years ago
6 0

Answer:

3xy

Step-by-step explanation:

We are to determine the GCF of the expression.

6(x^3)(y^3)+45(x^2)(y^2)+21xy

THe GCF of the expression is the term that exactly divides all the terms in the expression

<u>Step 1</u>

If we observe the expression carefully, we notice that it has a common term of 3, x and y. That is, 3,x and y divides each term.

<u>Step 2</u>

Divide by 3xy for confirmation

3xy\left(\dfrac{6(x^3)(y^3)}{3xy} +\dfrac{45(x^2)(y^2)}{3xy}+\dfrac{21xy}{3xy}\right)\\=3xy[2(x^2)(y^2)+15xy+7]

Therefore, we can confirm that the GCF is 3xy.

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