Here we have to get the effect of addition of 0.25 moles of gas C on the mole fraction of gas A in a mixture of gas having constant pressure.
On addition of 0.25 moles of C gas, the mole fraction of gas A will be
.
The partial pressure of gas A can be written as
=
×P (where
is the mole fraction of gas A present in the mixture and P is the total pressure of the mixture.
The mole fraction of gas A in a mixture of gas A and C is =
and
respectively.
Thus on addition of 0.25 moles of C gas, the mole fraction of gas A will be
.
Which is different from the initial state.
Basically for the first question, it’s 470.58 grams of potassium nitrate. Then for the second, it’s 0.34 moles of potassium nitrate. I hope the work makes sense!
Answer:
a. 473mL.
b. 79.38kg
c. 24.47lb of fat
d. 42.5g of N.
Explanation:
a. A qt is equal to 946mL. 0.500qt are:
0.500qt * (946mL / 1qt) = 473mL
b. 1lb is equal to 0.4536kg, 175lb are:
175lb *(0.4536kg / 1lb) = 79.38kg
c. The fat in kg of the athlete is:
74kg * 15% = 11.1kg of fat. In pounds:
11.1kg * (1lb / 0.4536kg) = 24.47lb of fat
d. The mass of nitrogen in the fertilizer is:
10.0oz * 15% = 1.5oz of N
1 oz is equal to 28.35g. 1.5oz are:
1.5oz * (28.35g / 1oz) = 42.5g of N
The differences are <u>the number of neutrons</u> and the <u>atomic mass</u><u /><u />.
Copper-63 has an atomic mass of 63 amu, and has 34 neutrons.
Copper-65 has an atomic mass of 65 amu, and has 36 neutrons.