True. light is particles. photons, however are waves.
<u>Answer:</u> The correct answer is Option a.
<u>Explanation:</u>
The reaction between sodium thiosulfate and nitric acid produces a number of products. The balanced chemical equation for the reaction of two follows:
![Na_2S_2O_3(aq.)+2HNO_3(aq.)\rightarrow 2NaNO_3(aq.)+H_2O(l)+SO_2(g)+S(s)](https://tex.z-dn.net/?f=Na_2S_2O_3%28aq.%29%2B2HNO_3%28aq.%29%5Crightarrow%202NaNO_3%28aq.%29%2BH_2O%28l%29%2BSO_2%28g%29%2BS%28s%29)
By Stoichiometry of the reaction:
1 mole of sodium thiosulfate reacts with 2 moles of nitric acid to produce 2 moles of sodium nitrate, 1 mole of water, 1 moles of sulfur dioxide and 1 mole of solid sulfur.
Hence, the correct answer is Option a.
Answer: The limiting reactants for the reaction is, Mg
Explanation : Given,
Mass of
= 10.1 g
Mass of
= 10.5 g
Molar mass of
= 24 g/mol
Molar mass of
= 32 g/mol
First we have to calculate the moles of
and
.
![\text{Moles of }Mg=\frac{\text{Given mass }Mg}{\text{Molar mass }Mg}](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20%7DMg%3D%5Cfrac%7B%5Ctext%7BGiven%20mass%20%7DMg%7D%7B%5Ctext%7BMolar%20mass%20%7DMg%7D)
![\text{Moles of }Mg=\frac{10.1g}{24g/mol}=0.421mol](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20%7DMg%3D%5Cfrac%7B10.1g%7D%7B24g%2Fmol%7D%3D0.421mol)
and,
![\text{Moles of }O_2=\frac{\text{Given mass }O_2}{\text{Molar mass }O_2}](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20%7DO_2%3D%5Cfrac%7B%5Ctext%7BGiven%20mass%20%7DO_2%7D%7B%5Ctext%7BMolar%20mass%20%7DO_2%7D)
![\text{Moles of }O_2=\frac{10.5g}{32g/mol}=0.328mol](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20%7DO_2%3D%5Cfrac%7B10.5g%7D%7B32g%2Fmol%7D%3D0.328mol)
Now we have to calculate the limiting and excess reagent.
The balanced chemical equation is:
![2Mg(s)+O_2(g)\rightarrow 2MgO(s)](https://tex.z-dn.net/?f=2Mg%28s%29%2BO_2%28g%29%5Crightarrow%202MgO%28s%29)
From the balanced reaction we conclude that
As, 2 mole of
react with 1 mole of ![O_2](https://tex.z-dn.net/?f=O_2)
So, 0.421 moles of
react with
moles of ![O_2](https://tex.z-dn.net/?f=O_2)
From this we conclude that,
is an excess reagent because the given moles are greater than the required moles and
is a limiting reagent and it limits the formation of product.
Hence, the limiting reactants for the reaction is, Mg