Question

What is the temperature of 0.750 mol of a gas stored in a 6,850 mL cylinder at 2.21 atm? Use PV=nRT and R=0.0821 (L•atm)/(mol•K)

Answer 1

Using the formula PV=nRT
we know:
n= 0.750mol
R= 0.0821 (L•atm)/(mol•K)
V= 6850 ml = 6.85 L
P= 2.21 atm
and we need to find T
all you have to do is divide PV by nR and you will find T, like this:
$t = \frac{p \times v}{n \times r} \\ t = \frac{2.21atm \times 6.85l}{0.750mol \times 0.0821 \frac{atm \times l}{mol \times k} } \\ t = 246k$
The temperature of the gas is D)246 K

Answer 2

Answer:

d.) 246 K

Explanation:

this is the answer on edge, i just took quiz

hope this helps!!!