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astraxan [27]
3 years ago
8

290°, rotate the terminal side 20° more in the counterclockwise direction

Mathematics
1 answer:
ikadub [295]3 years ago
6 0
the correct answer is 356 degrees hope that helps :) have a great day i hope u get it right because i don’t know it lol
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⎪6 − 4⎪ − ⎪3 − 8⎪ = ?<br> Please help!!!!
andriy [413]

Answer:

-3

Step-by-step explanation:

Numbers that come out of the absolute values are always positive.

|6 - 4| -|3 - 8| =

| 2| - | -5| =

2 - 5 =

-3

3 0
3 years ago
3/8 divided by 13/16
dedylja [7]

Answer:

Fraction= 6/13

Decimal= 0.4615

8 0
3 years ago
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In an all boys school, the heights of the student body are normally distributed with a mean of 70 inches and a standard deviatio
almond37 [142]

Answer:

0.010

Step-by-step explanation:

We solve the above question using z score formula

z = (x-μ)/σ, where

x is the raw score = 63 inches

μ is the population mean = 70 inches

σ is the population standard deviation = 3 inches

For x shorter than 63 inches = x < 63

Z score = x - μ/σ

= 63 - 70/3

= -2.33333

Probability value from Z-Table:

P(x<63) = 0.0098153

Approximately to the nearest thousandth = 0.010

Therefore, the probability that a randomly selected student will be shorter than 63 inches tall, to the nearest thousandth is 0.010.

3 0
3 years ago
How many times longer is the wavelength of a sound wave with a frequency of 20 waves per second than the wavelength of a sound w
sergejj [24]

The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

<h3>Calculating wavelength </h3>

From the question, we are to determine how many times longer is the first sound wave compared to the second sound water

Using the formula,

v = fλ

∴ λ = v/f

Where v is the velocity

f is the frequency

and λ is the wavelength

For the first wave

f = 20 waves/sec

Then,

λ₁ = v/20

For the second wave

f = 16,000 waves/sec

λ₂ = v/16000

Then,

The factor by which the first sound wave is longer than the second sound wave is

λ₁/ λ₂ = (v/20) ÷( v/16000)

= (v/20) × 16000/v)

= 16000/20

= 800

Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

Learn more on Calculating wavelength here: brainly.com/question/16396485

#SPJ1

6 0
2 years ago
5,309 divided by 43 5th grade lesson 2.6
pickupchik [31]
5,309 divided by 43 is equal to 123.4651162790698
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3 years ago
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