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3 years ago

I don’t understand I'm stupid, I don't understand mathematics :(

Mathematics

1 answer:

jekas [21]3 years ago

6 0

(1,-2) Don’t really know how I can explain it to you but this is the answer...

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10 6 4 15 6 8 6 15 4 find the median range of the data if necessary round to the nearest tenth

Lelu [443]

Reorder from least to greatest.

4, 4, 6, 6, 6, 8, 10, 15, 15

Median is the middle number.

This would be 6.

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hope it helps

8 0

3 years ago

Evaluate if f(x)=x+8+15,g(x)4x-2andh(x)=x-5x-14

Harlamova29_29 [7]

Answer is C! Hope it helps

7 0

3 years ago

What is 5 and 1/2 divided by 1/2 step by step ?? It would mean a lot!

dimulka [17.4K]

Answer:

Step-by-step explanation:

Use a calculator. Punch in 5.5, then use the divide symbol (÷) and finally put in 0.5, then you will get 11 as your final answer.

Hope this helps!

4 0

3 years ago

Simplify 3(7-3) the second power -4(6+2)

expeople1 [14]

Answer:

112

Step-by-step explanation:

3(7-3) = 3 x 4 = 12

12^2 = 144

144 -4(6+2)

144-4(8)

144-32

112

8 0

3 years ago

Read 2 more answers

The time between arrivals of taxis at a busy intersection is exponentially distributed with a mean of 10 minutes. (a) What is th

Sindrei [870]

Answer:

a) 0.0025

b) 0.9975

c) 23.03 minutes

d) 23.03 minutes

Step-by-step explanation:

Let X be the random variable that measures the time waited for a taxi.

If X is exponentially distributed with a mean of 10 minutes,then the probability that you have to wait more than t minutes is

$\large P(X>t) = e^{-t/10}$

1 hour = 60 minutes, so the probability that you wait longer than one hour is

$\large P(X>60)=e^{-6}=0.0025$

Due to the “memorylessness” of the exponential distribution, the probability that you have to wait 10 or less minutes after you have already waited for one hour, is the same as the probability that you have to wait 10 or less minutes

$\large P(X\leq 10)=1-e^{-6}=0.9975$

We want x so that

P(X>x)=0.1

$\large e^{-x/10}=0.1\rightarrow -x/10=ln(0.1)\rightarrow x=-10ln(0.1)=23.03\;minutes$

We want P(X<x)=0.9

$\large 1-e^{-x/10}=0.9\rightarrow e^{-x/10}=0.1\rightarrow x=-10ln(0.1)=23.03\;minutes$

4 0

3 years ago