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MAXImum [283]
3 years ago
10

"\frac{\sqrt[3]{60} }{\sqrt[3]{36} }" alt="\frac{\sqrt[3]{60} }{\sqrt[3]{36} }" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
Margarita [4]3 years ago
3 0
∛60
--------
∛36

=
∛5
------
∛3

=∛45
-----------
3

= 1.185
valentina_108 [34]3 years ago
3 0
Answer
1.185
Explanation
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Step-by-step explanation:

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Suppose you'd like to save enough money to pay cash for your next car. The goal is to save an extra $28,000 over the next 6 year
Anna35 [415]

Given:

• Amount to save, A = $28,000

,

• Time, t = 6 years

,

• Interest rate, r = 5.3% ==> 0.053

,

• Number of times compounded = quarterly = 4 times

Let's find the amount that must be deposited into the account quarterly.

Apply the formula:

FV=P(\frac{(1+\frac{r}{n})^{nt}-1}{\frac{r}{n}})

Where:

FV is the future value = $28,000

r = 0.053

n = 4

t = 6 years

Thus, we have:

28000=P(\frac{(1+\frac{0.053}{4})^{4\times6}-1)}{\frac{0.053}{4}}

Let's solve for P.

We have:

\begin{gathered} 28000=P(\frac{(1+0.01325)^{24}-1}{0.01325}) \\  \\ 28000=P(\frac{(1.01325)^{24}-1)^{}}{0.01325}) \\  \\ 28000=P(\frac{1.371509114-1}{0.01325}) \\  \\ 28000=P(\frac{0.371509114}{0.01325}) \end{gathered}

Solving further:

28000=P(28.0384237)

Divide both sides by 28.0384237:

\begin{gathered} \frac{28000}{28.0384237}=\frac{P(28.0384237)}{28.0384237} \\  \\ 998.6=P \\  \\ P=998.6 \end{gathered}

Therefore, the amount that must be deposited quarterly into the account is $998.60

ANSWER:

$998.60

8 0
1 year ago
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