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MAXImum [283]
3 years ago
10

"\frac{\sqrt[3]{60} }{\sqrt[3]{36} }" alt="\frac{\sqrt[3]{60} }{\sqrt[3]{36} }" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
Margarita [4]3 years ago
3 0
∛60
--------
∛36

=
∛5
------
∛3

=∛45
-----------
3

= 1.185
valentina_108 [34]3 years ago
3 0
Answer
1.185
Explanation
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Your drawer contains 6 gold earrings and 7 silver earrings. You randomly choose an earring. Without replacing the first, you cho
disa [49]

Answer:

The probability that both earrings are silver is 0.27.

Step-by-step explanation:

Basically, we have to pick in a such a way that the first earring is a silver earring and the second one is also a silver earring.

Constituents of the box= 7 silver, 6 gold.

Probability=\frac{No. Of Favorable Outcomes}{Total No. Of Outcomes}

Therefore, probability of picking up a silver earring in the first attempt(A)= \frac{7}{13}  

As we have picked up, one earring from the bag, the no. of silver earrings have been decreased by 1 as have the total no. of earrings.

Therefore, the total no. of earrings now=12

No. of silver earrings in the bag now=6

Probability of picking up a silver in the second attempt after the above first attempt(B)=\frac{6}{12}

P(A∩B)=P(A)*P(B)

            =\frac{7}{13} x \frac{6}{12}

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              =0.269

The probability that both earrings are silver is 0.27.

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