A train travels 150 miles in 3 hours. At this same rate, how many miles will it travel in 8 hours?

Help help help solve for x 2x + 3 /12 = 2x/8

pickupchik [31]

2x + 3 /12 = 2x/8
⇒ 48x/24 + 6/24 = 6x/24
⇒ (48x+ 6)/24= 6x/24
⇒ 48x+ 6 = 6x
⇒ 48x- 6x= -6
⇒ 42x= -6
⇒ x= -6/42
⇒ x= -1/7

x=-1/7~

6 0

4 years ago

Read 2 more answers

*Asymptotes* g(x) =2x+1/x-3 Give the domain and x and y intercepts

Nataly [62]

Answer: Assuming the function is $g(x)=\frac{2x+1}{x-3}$ :

The x-intercept is $(\frac{-1}{2},0)$ .

The y-intercept is $(0,\frac{-1}{3})$ .

The horizontal asymptote is $y=2$ .

The vertical asymptote is $x=3$ .

Step-by-step explanation:

I'm going to assume the function is: $g(x)=\frac{2x+1}{x-3}$ and not $g(x)=2x+\frac{1}{x}-3$ .

So we are looking at $g(x)=\frac{2x+1}{x-3}$ .

The x-intercept is when y is 0 (when g(x) is 0).

Replace g(x) with 0.

$0=\frac{2x+1}{x-3}$

A fraction is only 0 when it's numerator is 0. You are really just solving:

$0=2x+1$

Subtract 1 on both sides:

$-1=2x$

Divide both sides by 2:

$\frac{-1}{2}=x$

The x-intercept is $(\frac{-1}{2},0)$ .

The y-intercept is when x is 0.

Replace x with 0.

$g(0)=\frac{2(0)+1}{0-3}$

$y=\frac{2(0)+1}{0-3}$

$y=\frac{0+1}{-3}$

$y=\frac{1}{-3}$

$y=-\frac{1}{3}$ .

The y-intercept is $(0,\frac{-1}{3})$ .

The vertical asymptote is when the denominator is 0 without making the top 0 also.

So the deliminator is 0 when x-3=0.

Solve x-3=0.

Add 3 on both sides:

x=3

Plugging 3 into the top gives 2(3)+1=6+1=7.

So we have a vertical asymptote at x=3.

Now let's look at the horizontal asymptote.

I could tell you if the degrees match that the horizontal asymptote is just the leading coefficient of the top over the leading coefficient of the bottom which means are horizontal asymptote is $y=\frac{2}{1}$ . After simplifying you could just say the horizontal asymptote is $y=2$ .

Or!

I could do some division to make it more clear. The way I'm going to do this certain division is rewriting the top in terms of (x-3).

$y=\frac{2x+1}{x-3}=\frac{2(x-3)+7}{x-3}=\frac{2(x-3)}{x-3}+\frac{7}{x-3}$

$y=2+\frac{7}{x-3}$

So you can think it like this what value will y never be here.

7/(x-3) will never be 0 because 7 will never be 0.

So y will never be 2+0=2.

The horizontal asymptote is y=2.

(Disclaimer: There are some functions that will cross over their horizontal asymptote early on.)

6 0

3 years ago

Story Problem

Agata [3.3K]

Answer:

41.15

Step-by-step explanation:

41.15

7 0

3 years ago

Which of the following statements best describes the location of −(−2) on a number line? It is 2 units to the right of 0. It is

ivolga24 [154]

Let say x = -(-2) where x is the distance of number on number line from 0.
x = -(-2)
x = +2.
Since +2 is positive quantity, positive quantities are written to the right of 0 on number line.
Hence it is 2 units to the right of 0.

3 0

3 years ago

You are currently paying rent every year for your restaurant. You still have a contract that will last 2 more years. Starting to

Andreas93 [3]

The amount to be paid in rent after 2 years if the rent as of now is $3,000 will be; $3,213.675

The question allows that we choose the amount being paid as rent as of now.

Let the rent paid as of now be; $3,000

In essence; after the first year; the amount increases by 3.5% to become;

1.035 × $3,000

= $3,105.

After the second year; we have;

1.035 × $3,105

= $3,213.675

Ultimately; the amount to be paid after 2 years will be; $3,213.675.

When given the opportunity to change rent contracts;

A situation that will be beneficial would be a 3.5% reduction in rent per year
A situation that will not be beneficial would be a 7% increase in rent per year.