Answer:
See below
Step-by-step explanation:
I'll provide an example to help you. Let's say we were solving 
and we wanted to factor the quadratic on the left side. We can't do that because the factors of -7 don't add up to 5. So we'd have to use the quadratic formula. The quadratic formula is essentially the last resort that will solve all quadratic equations, so it could be seen as a preferred method. But, unless you can factor the quadratic, it's much easier to solve.
Now let's do another one. 
for example can be written as 
and we can easily get 
and 
as solutions since plugging them into the factors would produce 0 (from the Zero Product Property). If we used the quadratic formula, it would take more time to plug in the variables and solve when we can just simply factor.
Hopefully, this explanation helps you to think of your discussion post!
Answer:
6,200
Step-by-step explanation:
19-20
307-310
310 x 20= 6,200 or 20 x 310= 6,200
Answer:
g(x) = x+1
Step-by-step explanation:
Informally, you can see that the function h(x) takes the root of a value that is 1 more than the value under the same radical in f(x). This suggests that adding 1 to x in f(x) will give you h(x). That is, ...
h(x) = f(x+1) = f(g(x))
so
g(x) = x+1
_____
More formally, you can apply the inverse of the function f(x) to the equation ...
h(x) = f(g(x))
f^-1(h(x)) = f^-1(f(g(x))) . . . inverse function applied
f^-1(h(x)) = g(x) . . . . . . . . . simplified
Now f^-1(x) can be found by solving for y in ...
x = f(y)
x = ∛(y+2) . . . . . . . . . definition of f(y)
x^3 = y+2 . . . . . . . . . cube both sides
x^3 -2 = y = f^-1(x) . . . subtract 2 from both sides
So, f^-1(h(x)) is ...
f^-1(h(x)) = g(x) = (∛(x+3))^3 -2 = x+3 -2
g(x) = x+1
Answer: X=9
x^2 −2(x) (9)+9^2 =0
(X-9)^2=0
X-9=0
X=9
The answer is 12/16... divide the fraction by 4 and you get 3/4
