Answer:The absolute value of a number is its distance away from zero. That number will always be positive, as you cannot be negative two feet away from something. So any absolute value equation set equal to a negative number is no solution, regardless of what that number is.
Step-by-step explanation:
there u go
When the function goes 1 to the right, it goes 2 down. Therefore the direction of the function is
Hence, the function represented is
y = -2x
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As already described above, the prime polynomial is that which can no longer be factored to yield a much simpler terms. From the given choices, that which cannot be factored is letter C.
Step-by-step explanation:
slope formula when it's perpendicular : m1 × m = -1
Now Differentiate the quadratic function given.
d/dx ( x^2 - x + 1 ) at an x value of -1 from the point "(-1 , 3 )"
= 2x - 1 .... plug in the x value
= 2 × -1 - 1 = -3.
Use this equation...
y - y1 = m(x - x1)
m = slope = derivative at x = -1
y1 = value found by subbing -1 into the original function
x1 = the x value often given.
y - 3 = 1/3 (x + 1)
= 1/3x + 1/3 + 3
y = 1/3x + 10/3.
not sure about this one - it probably intersects at the x & y intercepts of the equation of the normal line.
y = 0 + 10/3 = 10/3
1/3x = 0 - 10/3
x = -10/3 / 1/3 = -10
so the point .... (-10 , 10/3)
