5/6 of 300 is 250 people that completed the course.
Answer:
Question 4: Which equation is parallel to the above equation and passes through the point (35, 30)
is the correct answer, I found this by inputting the x and y value of the coordinate (35, 30) onto the equation and solving for y-intercept since the slope of all equations is the same (since it's traveling parallel)
so the equation would be
Question 5: Which equation is perpendicular to the above equation and passes through the point (35, 30)
is the correct answer, I found this using the same method as before, input coordinate values into the equation and solve for the y-intercept (The only thing changed from the last answer is the opposite reciprocal slope).
so the equation would be
That is impossible to answer because this is an expression. you can only solve for x in equations
Answer:
31.9secs
6,183.3m
Step-by-step explanation:
Given the equation that models the height expressed as;
h(t ) = -4.9t²+313t+269
At the the max g=height, the velocity is zero
dh/dt = 0
dh/dt = -9,8t+313
0 = -9.8t + 313
9.8t = 313
t = 313/9.8
t = 31.94secs
Hence it takes the rocket 31.9secs to reach the max height
Get the max height
Recall that h(t ) = -4.9t²+313t+269
h(31.9) = -4.9(31.9)²+313(31.9)+269
h(31.9) = -4,070.44+9,984.7+269
h(31.9) = 6,183.3m
Hence the maximum height reached is 6,183.3m
Answer:
x is equal to 4.3
Step-by-step explanation:
since it's -4.3 + x is equal to 0
you take -4.3 to the other side of the equal sign which makes it positive and x is equal to 4.3
