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Veseljchak [2.6K]
3 years ago
13

There..?

Mathematics
1 answer:
QveST [7]3 years ago
3 0

The answer should be:

Domain: All real

numbers

greater than or

equal to 0 and

less than or

equal to 100

Range: all real

numbers

greater than or

equal to 0 and

less than or

equal to 50

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Covert 1/16in to mm (rounded to the nearest tenth)
mel-nik [20]
1/25.4 = (1/16)/x....1 in to 25.4mm = 1/16 in to x mm
cross multiply
x = 25.4 * 1/16
x = 25.4/16
x = 1.59 mm
3 0
3 years ago
How are y-intercepts of y=(1/3)^x and y=5(1/3)^x different?
loris [4]
Remark.
The easiest way to do this question is to graph it. Start with that.
The red line is y = (1/3)^x
The blue line is y = 5*(1/3)^x

Comment
The red line's y intercept is (0,1)
The blue line's y intercept is (0,5)

Why
If the x value is 0 then (1/3)^0 = 1
y = (1/3)^0 = 1 * 1 = 1 and for the blue graph
y =  5*(1/3)^0 = 5*1 = 5

In other words, in this set of equations, the 5 makes the y intercept 5 times larger than the 1 in front of y = (1/3)^x

If you have choices, could you please list them? I may be giving you the right answer but not in the form required.

7 0
3 years ago
Read 2 more answers
The sum of the first n consecutive even numbers can be found using S=n2+n, where n≥2. What is the value of n when the sum is 42?
lawyer [7]

Answer:

  • C. 6

Step-by-step explanation:

<u>Given</u>

  • S = n² + n
  • S = 42, n = ?

<u>Substitute and solve for n:</u>

  • 42 = n² + n
  • n² + 2*1/2n + 1/4 = 42.25
  • (n + 0.5)² = 42.25
  • n + 0.5 = √42.25
  • n + 0.5 = 6.5
  • n = 6

Correct option is C

5 0
3 years ago
Read 2 more answers
19. A quadratic equation is shown below.
victus00 [196]

Answer:

\{\sqrt b, -\sqrt b\}

Step-by-step explanation:

Given

a^2 - b = 0

Required

Determine the solution

Since b is  a perfect square, the equation can be expressed as:

a^2 - (\sqrt b)^2 = 0

Apply difference of two squares:

(a - \sqrt b)(a + \sqrt b) = 0

Split:

(a - \sqrt b)= 0 \ or\ (a + \sqrt b) = 0

Remove brackets:

a - \sqrt b= 0 \ or\ a + \sqrt b = 0

Make a the subject in both equations

a =\sqrt b \ or\ a  =-\sqrt b

The solution can be represented as:

\{\sqrt b, -\sqrt b\}

6 0
3 years ago
Find all solutions to the equation.<br><br> cos^2x + 2 cos x + 1 = 0
natali 33 [55]

\bf cos^2(x)+2cos(x)+1=0\implies \stackrel{\textit{let's notice, this is simply }ax^2+bx+c=0}{[cos(x)]^2+2cos(x)+1=0} \\[2em] [cos(x)+1][cos(x)+1]=0 \\\\[-0.35em] ~\dotfill\\\\ cos(x)+1=0\implies cos(x)=-1\implies x=cos^{-1}(-1)\implies \stackrel{\textit{for the range }[0,2\pi ]}{x=\pi } \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{\textit{all solutions}}{x=\pi +2\pi n~~,~~ n \in \mathbb{Z}}~\hfill

6 0
3 years ago
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