Answer:
The percentage of the bank's customers carry daily balances between $700 and $1,000 is 65.7%.
The minimum daily balance on which it should be willing to pay interest is $1,198.
Step-by-step explanation:
We have a normal distribution with mean = $800 and standard deviation = $150.
a) We can calculate this value with the standard normal distribution, calculating the z-value for $700 and $1,000.
The percentage of the bank's customers carry daily balances between $700 and $1,000 is 65.7%.
b) We must calculate from what amount only 6% of the accounts remain.
This is done by solving:
This happens for a z-value of z=2.652.
This corresponds to a amount of $1,198.
The minimum daily balance on which it should be willing to pay interest is $1,198.
54 55 59 61 61 62 68 70 72
First put your numbers in order from least to greatest. This shows your minimum is 54 and maximum is 72.
In the middle of the data set is 61.
54 55 59 61. 61. 62 68 70 72
To find the first qaurtile only use the numbers before rhe median (54 55 59 61) and find the median of that. Since 55 and 59 are both in the middle add them both and divide by two to find the middle lf those two numbers. You should get 57. So 57 is the first quartile.
Do the same steps with the numbers after the meadian for your third quartile. You should get 69 as your answer for the third quartile.
Answer: −14a−4
Step-by-step explanation: