<span>Given that Devorah
is filling a pool with a hose. The volume.H. In liters, of water coming
out of the hose in .m.minutes is given by the function H(m)=17.4m.
However it is a sunny day, and water is also evaporating from the pool.
Therefore,the volume ,V, in liters, of water in the pool m minutes after
devorah started filling it is given by V(m)=17m.
IfE be the volume of water, In Liters ,that has evaporated from the pool m minutes after devorah started filling it .
The formula for E(m) in terms of H(m) and V(m) is given by
E(m) = H(m) - V(m)
And
The formula for E(m) in terms of m is given by
E(m) = 17.4m - 17m = 0.4m</span>
3 for 3.60 the unit price come out to 1.20
I am hoping that the a in c = ad is supposed to be x.
The formula for circumference is c = pi * diameter with 3.14 substituting for pi.
Let’s plug in some values
172.7 = 3.14d
Divide
55 = d
The diameter should be 55 cm.
Answer: 0.0930
Step-by-step explanation:
As per given , we have
H0: μcoffee = 6
Ha: μcoffee < 6
She finds z = −1.68 with one-sided P-value P = 0.0465.
The P-value for two-tailed test is calculated by :
For z= -1.68 , we have
![=2(1-P(z\leq1.68))\ \ [\because\ P(Z>z)=1-P(Z\leq z)]](https://tex.z-dn.net/?f=%3D2%281-P%28z%5Cleq1.68%29%29%5C%20%5C%20%5B%5Cbecause%5C%20P%28Z%3Ez%29%3D1-P%28Z%5Cleq%20z%29%5D)
![=2(1-0.9535213)\ \ \ [\text{ NORM.S.DIST(z, TRUE}]\\\\=2( 0.0464787)=0.0929573\approx0.0930](https://tex.z-dn.net/?f=%3D2%281-0.9535213%29%5C%20%5C%20%5C%20%5B%5Ctext%7B%20NORM.S.DIST%28z%2C%20TRUE%7D%5D%5C%5C%5C%5C%3D2%28%200.0464787%29%3D0.0929573%5Capprox0.0930)
Hence, the correct two-sided P-value for z = −1.68 is 0.0930 .
Answer:Answer: point (3,-4) is 3 units to the right of the origin and 4 down
Step-by-step explanation: easiest to graph
