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3 years ago

Chad bought a pair of jeans that cost $54, but his total was $58.32 due to the

Mathematics

1 answer:

Dima020 [189]3 years ago

5 0

Answer:

Step-by-step explanation:

58.32-54= 4.32

8% of 54 is 4.32

54+4.32= 58.32

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the price of a cup of coffee has dropped to $2.20 today. Yesterday's price was $2.35. Find the percentage decrease. Round your a

notka56 [123]

Answer:

6.4%

Step-by-step explanation:

percentage decrease= decrease/actually amount×100

2.35-2.20/2.35×100

0.15/2.35×100

0.06383×100=6.4%

Percentage decrease=6.4%

6 0

2 years ago

At 10 am a 6-foot- tall man casts a 4.5 foot shadow. How long a shadow cast by a 50-foot tree?

vaieri [72.5K]

6 foot makes 4.5 foot shadow
1 foot makes=4.5/6
so 50 foot =4.5/6*50 = tree makes 37.5 foot shadow

4 0

3 years ago

Simplify each expression involving signed numbers.

7nadin3 [17]

Answer:

-7 - 2 = -9 (combine the numbers,simplify)

12 + (-4) = 8 (Simplify the Expression)

-8(-6) = 48 (Simplify the Expression)

18/-3 = -6 ( Simplify the Expression)

Hope this helps :)

3 0

2 years ago

Read 2 more answers

An arithmetic sequence is represented in the following table. Enter the missing term of the sequence.

Allisa [31]

Answer:

329.5

Step-by-step explanation:

From the table we see that the common difference d = 0.5 - (-6.5)

= 7, and 7.5 - 0.5 = 7. Also 14.5 - 7.5 = 7.

The first term a1 = -6.5.

The nth term = a1 + (n - 1)d so for our sequence we have:

49th term = -6.5 + (49 - 1)7

= -6.5 + 48 * 7

= -6.5 + 336

= 329.5 (answer).

4 0

3 years ago

Location is known to affect the number, of a particular item, sold by an auto parts facility. Two different locations, A and B,

Mama L [17]

We have two samples, A and B, so we need to construct a 2 Samp T Int using this formula:

$\displaystyle \overline {x}_1 - \overline {x}_2 \ \pm \ t^{*} \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} }$

In order to use t*, we need to check conditions for using a t-distribution first.

Random for both samples -- NOT STATED in the problem ∴ proceed with caution!
Independence for both samples: 130 < all items sold at Location A; 180 < all items sold at Location B -- we can reasonably assume this is true
Normality: CLT is not met; n < 30 for both locations A and B ∴ proceed with caution!

Since 2/3 conditions aren't met, we can still proceed with the problem but keep in mind that the results will not be as accurate until more data is collected or more information is given in the problem.

Solve for t*:

We need the tail area first.

$\displaystyle \frac{1-.9}{2}= .05$

Next we need the degree of freedom.

The degree of freedom can be found by subtracting the degree of freedom for A and B.

The general formula is df = n - 1.

df for A: 13 - 1 = 12
df for B: 18 - 1 = 17
df for A - B: |12 - 17| = 5

Use a calculator or a t-table to find the corresponding t-score for df = 5 and tail area = .05.

t* = -2.015

Now we can use the formula at the very top to construct a confidence interval for two sample means.

$\overline {x}_A=39$
$s_A=8$
$n_A=13$
$\overline {x}_B = 55$
$s_B=2$
$n_B=18$
$t^{*}=-2.015$

Substitute the variables into the formula: $\displaystyle \overline {x}_1 - \overline {x}_2 \ \pm \ t^{*} \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} }$ .

$39-55 \ \pm \ -2.015 \big{(}\sqrt{\frac{(8)^2}{13} +\frac{(2)^2}{18} } } \ \big{)}$

Simplify this expression.

$-16 \ \pm \ -2.015 (\sqrt{5.1453} \ )$
$-16 \ \pm \ 3.73139$

Adding and subtracting 3.73139 to and from -16 gives us a confidence interval of:

$(-20.5707,-11.4293)$

If we want to interpret the confidence interval of (-20.5707, -11.4293), we can say...

We are 90% confident that the interval from -20.5707 to -11.4293 holds the true mean of items sold at locations A and B.

5 0

1 year ago