If b is the base then the height h=b+6. As we have S=bh/2 then
36=b(b+6)/2;
b²+6b-72=0;
D/4=3²+72=81
b₁=-3-9=-12
b₂=-3+9=6.
The base is always positive so b=6, h=6+6=12.
Answer: base=6 ft, height=12 ft.
The equation represents a line that passes through(4, 1/3) and has a slope of 3/4 option A; y - 1/3 = 3/4 ( x - 4).
<h3>What is the Point-slope form?</h3>
The equation of the straight line has its slope and given point.
If we have a non-vertical line that passes through any point(x1, y1) has gradient m. then general point (x, y) must satisfy the equation
y-y₁ = m(x-x₁)
Which is the required equation of a line in a point-slope form.
we know that
The equation of the line into point-slope form is equal to
y-y₁ = m(x-x₁)
we have
(x₁, y₁) = (4, 1/3)
m = 3/4
substitute the given values
y-y₁ = m(x-x₁)
y - 1/3 = 3/4 ( x - 4)
therefore,
y minus StartFraction one-third EndFraction equals StartFraction 3 Over 4 EndFraction left-parenthesis x minus 4 right-parenthesis.(x – 4)
Thus, option A is correct.
Learn more about slope;
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Step-by-step explanation:
g of load= 30 kg ( kilogram)
load at top of building=20 kg( kilogram)
building height=13 m(meter)
<h2>or"= total work done=?</h2>
<h3> or"=. power developed by him= ? </h3>
now ,
30*20*13÷20
again ,30*20*13
________
20
answer,= 390
Recall the formula for finding the area of a rectangle:
Area = Length × Width
Recall the formula for finding the perimeter of a rectangle:
Perimeter = 2 ( Length + Width )
Given in your problem:
Area = 40 sq. units
Perimeter = 26 units
Required to solve for:
Length (L) and width (W)
• First, substitute the given to the formula:
Area = Length x Width
40 = L × W ⇒ equation number 1
Perimeter = 2 ( Length + Width )
26 = 2 ( L + W ) ⇒ equation number 2
• Simplifying equation number 2,
13 = L + W
• Rearranging the equation,
L = 13 - W ⇒ equation 3
Substituting equation 3 from equation 1:
( equation 1 ) 40 = (L)(W)
( equation 3 ) L = 13 - W
40 = (13 - W) (W)
40 = 13W - W²
( regrouping ) W² - 13W + 40 = 0
( factoring ) (W - 8) (W - 5) = 0
W - 8 = 0 ; W - 5 = 0
W = 8 ; W = 5
Therefore, there are 2 possible values for the width of the rectangle. It can be 8 units or 5 units.
• Now to solve for the length of the rectangle, substitute the two values of width to equation 3.
(equation 3) L = 13 - W
for W = 8 ⇒ L = 13 - 8
L = 5 units
for W = 5 ⇒ L = 13 - 5
L = 8 units
