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Dmitry [639]
3 years ago
6

A man bough a dozen boxes, wach with 24 highlighter pens inside, for $8.00 each box. He repacked five of these boxes into packag

es of six highlighters each and sold them for $3.00 per package. He sold the rest of the highlighters separately at the rate of three pens for $2.00. How much profit did he make?
Mathematics
2 answers:
Andreas93 [3]3 years ago
7 0
A dozen boxes is 12 boxes, with 24 pens inside. So, the man had a total of 288 highlighters pens to start with. he then repackaged 5 boxes times six highlighters =30 highlighters taken from original 288. He sold for $3.00 times 5 boxes =15$ He originally spent $96 to purchase his highlighters. So 288-30 =258pens left after repackaged boxes..   258 divided by 3=86. 86 times 2$=172$ So 172$ plus $15= 187 $. Subtract $96 spent from $187 resale value, and you get a profit of 91$
Marina CMI [18]3 years ago
5 0
He made a profit of $8
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3 years ago
the difference of two numbers is eight the first number x is one less than twice the second number y write and solve a system of
jeka94
<h3>Answer:</h3>

The two numbers are 17 and 9.

<h3>Explanation:</h3>

<em>System of Equations</em>

Let x and y represent the first and second numbers, respectively.

... x - y = 8 . . . . . . . . . the difference of the two numbers is 8

... x = 2y - 1 . . . . . . . . .the first number is one less than twice the second

<em>Solution</em>

The second equation gives an expression for x that can be substituted into the first equation.

... (2y -1) -y = 8

... y -1 = 8 . . . . . . . collect terms

... y = 9 . . . . . . . . . add 1

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4 years ago
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Answer:

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