A probability experiment consists of rolling a fair 10 sided die. probability of rolling a 1

Mathematics

1 answer:

ki77a [65]3 years ago

6 0

It would be 1/10 i believe

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The graph shown represents the graph of an inequality. The boundary tells you that ________.

kaheart [24]

Can I have an image of the graph?

8 0

3 years ago

Two sides of an isosceles triangle have lengths of 3 and 10. Find the length of the third side.

lora16 [44]

Answer:

The third side must be 10: {3, 10, 10}; {10, 3, 3} is not possible.

Step-by-step explanation:

Everything depends on our understanding of "isosceles."

This term indicates that two sides of a given triangle are equal.

If two sides of an isosceles triangle have lengths of 3 and 10, then:

Either 1) Two sides have length 10 and the third side has length 3. This is certainly possible

2) sides have length 3 and the third side has length 10. This is NOT possible, since 3 + 3 adds up to 6, which is less than 10.

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3 years ago

Sound travels through sea water at a speed of about 1500 meters per second. At this rate, how far will sound travel in 2 minutes

Mariulka [41]

Answer:

180,000 m

Step-by-step explanation:

There are 60 seconds in a minute, so:

2 min × 60 s/min = 120 s

Distance = rate × time

d = 1500 m/s × 120 s

d = 180,000 m

8 0

3 years ago

write a linear equation that intersects y=x^2 at two points. Then write a second linear equation that intersects y=x^2 at just o

Liula [17]

We know that $y = x^2$ is a parabola, concave up, with vertex in the origin $(0,0)$

So, we may use three horizontal lines for our purpose: any horizontal line above the x axis will intersect the parabola twice. The x axis itself intersects the parabola once on the vertex, while any horizontal line below the x axis won't intercept the parabola.

Here's the examples:

The horizontal line $y = 4$ intercepts the parabola twice: the system $y = x^2,\ y = 4$ is solved by $x^2=4 \implies x = \pm 2$
The horizontal line $y=0$ intercepts the parabola only once: the system is $y=x^2,\ y=0$ which yields $x^2=0\implies x=0$ which is a repeated solution
The horizontal line $y=-5$ intercepts the parabola only once: the system is $y=x^2,\ y=-5$ which yields $x^2=-5$ which is impossible, because a squared number can't be negative.