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Check the picture.
since the choices all have rotation about the origin, we must shift the original triangle in a suitable position. This is done by connecting any of the points of A'B'C' to the origin, and extend this line segment, as shown in the picture.
The most appropriate point is C', and we draw C" such that C'O=OC", and C', O and C" are collinear.
We see that the distance CC'' is 5.
So
Answer is:
"<span>A translation 5 units down, followed by a 180-degree counterclockwise rotation about the origin</span>"
since the choices all have rotation about the origin, we must shift the original triangle in a suitable position. This is done by connecting any of the points of A'B'C' to the origin, and extend this line segment, as shown in the picture.
The most appropriate point is C', and we draw C" such that C'O=OC", and C', O and C" are collinear.
We see that the distance CC'' is 5.
So
Answer is:
"<span>A translation 5 units down, followed by a 180-degree counterclockwise rotation about the origin</span>"
In the given triangle, y = 32°.
Step-by-step explanation:
Step 1; In the given triangle, the opposite side has a length of 9cm while the hypotenuse of the triangle measures 17cm. As we have the lengths of the opposite side and the hypotenuse side, we can calculate the sine of the value y.
sin y = .
Step 2; Length of the opposite side = 9 cm.
Length of the hypotenuse side = 17 cm.
sin y = =
= 0.5294.
We can multiply inverse sine on both sides to solve y.
y = (0.5294) = 31.9657°.
Rounding this off to the nearest tenth we get, y = 32.0°.