3 years ago

\frac{h^{2}-1 }{h+3} when h=5

Mathematics

1 answer:

umka21 [38]3 years ago

8 0

Answer:

Step-by-step explanation:

$\frac{h^{2}-1 }{h+3}$ =

$\frac{5^{2}-1 }{5+3}$ =

$\frac{25-1}{8}$ =

$\frac{24}{8}$ =

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